我想在一维反应-扩散-ODE系统的显式有限差分数值方案中实现周期性边界条件。但是,我不是这方面的专家,因此我们将非常感谢任何帮助。代码(我目前有 Neumann 边界条件)如下:
clear all
close all
tic
Fig=figure('Position',[100 100 1200 600]); % Figure Settings [left, bottom, width, height]
% Spatial discretisation
DeltaX=0.05;
% Parameter values
a=0.2;
b=0.15;
h=0.2;
d=10;
epsilon=0.01;
k=0.3;
% Number of grid cells
m=400;
NX=m;
% Timesteps
dt=0.0002;
Time=0;
EndTime=100000;
PlotStep=10;
PlotTime=PlotStep;
% Initialisation
V = zeros(1,m);
U = zeros(1,m);
S = zeros(1,m);
dV=zeros(1,m);
dU=zeros(1,m);
dS= zeros(1,m);
NetV=zeros(1,m);
NetU=zeros(1,m);
% Boundary conditions
% Neumann
FXV = zeros(1,NX+1); % bound.con. no flow in/out to X-direction
FXU = zeros(1,NX+1); % bound.con. no flow in/out to X-direction
% Initial state for V
for i=1:NX
if (i <= NX/2)
V(i)=0.6;
else
V(i)=0;
end
end
% Initial state for U
U(:)=61.5;
% figtitle = sgtitle('Time: 0');
figtitle=sgtitle(['A = ' num2str(a) ', B=' num2str(b) ', H=' num2str(h) ', D=' num2str(d) ', eps=' num2str(epsilon) ', k=' num2str(k)]);
index=1;
% Timesteps
while Time<=EndTime
% Reaction
dV= U.*V.^2 -k*U.*V.^3 -b*V-h*S.*V;
dU= a*(1-U)-U.*V.^2;
dS= (1/d)*(b*V+h*S.*V-S);
VU=max(0,U);
% Diffusion
FXV(2:NX)=(V(2:NX)-V(1:NX-1))/DeltaX; % flow in x-direction : dV/dx;
NetV=(epsilon^2)*(FXV(2:NX+1)-FXV(1:NX))/DeltaX; % eps^2 * vector for Laplacian differences
FXU(2:NX)=(VU(2:NX)-VU(1:NX-1))/DeltaX; % flow in x-direction : dU/dx;
NetU=(FXU(2:NX+1)-FXU(1:NX))/DeltaX; % vector for Laplacian differences
% Update
V=V+(NetV+dV)*dt;
U=U+(NetU+dU)*dt;
S=S+dS*dt;
Time=Time+dt;
PlotTime=PlotTime-dt;
if PlotTime<=0.00001
figure(1)
% V plot
subplot(1,3,1)
plot(V)
xlabel('x');
ylabel('V');
ylim([0 3]);
% U plot
subplot(1,3,2)
plot(U)
xlabel('x');
ylabel('U');
ylim([0 1]);
% S plot
subplot(1,3,3)
plot(S)
xlabel('x');
ylabel('S');
ylim([0 2]);
PlotTime=PlotStep;
end
end