我认为您可能想要的只是将两个图像的大小调整为相同的大小,然后添加它们。然后使用遮罩在 Python/OpenCV 中进行强光合成。
图像1:

图像2:

掩码(显着性):

import cv2
import numpy as np
# read image 1
img1 = cv2.imread('img1.png')
hh, ww = img1.shape[:2]
# read image 2 and resize to same size as img1
img2 = cv2.imread('img2.png')
img2 = cv2.resize(img2, (ww,hh))
# read saliency mask as grayscale and resize to same size as img1
mask = cv2.imread('mask.png')
mask = cv2.cvtColor(mask, cv2.COLOR_BGR2GRAY)
mask = cv2.resize(mask, (ww,hh))
# add img1 and img2
img12 = cv2.add(img1, img2)
# get mean of mask and shift mean to mid-gray
# desirable for hard light compositing
# add bias as needed
mean = np.mean(mask)
bias = -32
shift = 128 - mean + bias
mask = cv2.add(mask, shift)
mask = cv2.merge([mask,mask,mask])
# threshold mask at mid gray and convert to 3 channels
# (needed to use as src < 0.5 "if" condition in hard light)
thresh = cv2.threshold(mask, 128, 255, cv2.THRESH_BINARY)[1]
# do hard light composite of img12 and mask
# see CSS specs at https://www.w3.org/TR/compositing-1/#blendinghardlight
img12f = img12.astype(np.uint8)/255
maskf = mask.astype(np.uint8)/255
threshf = thresh.astype(np.uint8)/255
threshf_inv = 1 - threshf
low = 2.0 * img12f * maskf
high = 1 - 2.0 * (1-img12f) * (1-maskf)
result = ( 255 * (low * threshf_inv + high * threshf) ).clip(0, 255).astype(np.uint8)
# save results
cv2.imwrite('img12_hardlight.png', result)
# show results
cv2.imshow('img12', img12)
cv2.imshow('mask', mask)
cv2.imshow('thresh', thresh)
cv2.imshow('result', result)
cv2.waitKey(0)
cv2.destroyAllWindows()
结果:
