我的代码本身工作正常,我想知道是否有更简单的方法来确定是否至少检查了我的一个菜单项。
语境
菜单被 a 使用,CMFCMenuButton
如下所示:
行为
菜单本质上是一组选中的菜单项,用户可以根据需要进行切换。然后,应用程序会根据这些菜单项的状态执行一些操作。基本的东西。
目前我有这个代码片段(工作正常):
MSAToolsLibrary::IPublisherPtr pPublisher = nullptr;
if (theApp.MSAToolsInterface().GetPublisher(aryStrNames[i], pPublisher))
{
bool bAdd = false;
MSAToolsLibrary::Serving eServing;
MSAToolsLibrary::Appointed eAppointed;
pPublisher->get_ServingAs(&eServing);
pPublisher->get_AppointedAs(&eAppointed);
bool bNoExtraPublisherFilter = true;
if (m_menuExtraPublisherFilter.GetMenuState(ID_PUBLISHERS_DATABASE_EXTRA_FILTER_UNBAPTISED_PUBLISHER, MF_BYCOMMAND) == MF_CHECKED)
{
bNoExtraPublisherFilter = false;
if (eServing == MSAToolsLibrary::Serving_UnbaptisedPublisher)
bAdd = true;
}
if (m_menuExtraPublisherFilter.GetMenuState(ID_PUBLISHERS_DATABASE_EXTRA_FILTER_PUBLISHER, MF_BYCOMMAND) == MF_CHECKED)
{
bNoExtraPublisherFilter = false;
if (eServing == MSAToolsLibrary::Serving_Publisher)
bAdd = true;
}
if (m_menuExtraPublisherFilter.GetMenuState(ID_PUBLISHERS_DATABASE_EXTRA_FILTER_REGULAR_PIONEER, MF_BYCOMMAND) == MF_CHECKED)
{
bNoExtraPublisherFilter = false;
if (eServing == MSAToolsLibrary::Serving_RegularPioneer)
bAdd = true;
}
if (m_menuExtraPublisherFilter.GetMenuState(ID_PUBLISHERS_DATABASE_EXTRA_FILTER_OTHER, MF_BYCOMMAND) == MF_CHECKED)
{
bNoExtraPublisherFilter = false;
if (eServing == MSAToolsLibrary::Serving_Other)
bAdd = true;
}
if (m_menuExtraPublisherFilter.GetMenuState(ID_PUBLISHERS_DATABASE_EXTRA_FILTER_NOT_APPOINTED, MF_BYCOMMAND) == MF_CHECKED)
{
bNoExtraPublisherFilter = false;
if (eAppointed == MSAToolsLibrary::Appointed_NotAppointed)
bAdd = true;
}
if (m_menuExtraPublisherFilter.GetMenuState(ID_PUBLISHERS_DATABASE_EXTRA_FILTER_MINISTERIAL_SERVANT, MF_BYCOMMAND) == MF_CHECKED)
{
bNoExtraPublisherFilter = false;
if (eAppointed == MSAToolsLibrary::Appointed_MinisterialServant)
bAdd = true;
}
if (m_menuExtraPublisherFilter.GetMenuState(ID_PUBLISHERS_DATABASE_EXTRA_FILTER_ELDER, MF_BYCOMMAND) == MF_CHECKED)
{
bNoExtraPublisherFilter = false;
if (eAppointed == MSAToolsLibrary::Appointed_Elder)
bAdd = true;
}
if(bNoExtraPublisherFilter)
{
// None of the menu items were checked
bAdd = true;
}
if(bAdd)
m_lbPublishers.AddString(aryStrNames[i]);
}
我只是想知道是否有更快的方法来查看是否没有设置任何菜单项MF_CHECKED
?因为如果可以检测到这种情况,我可以GetPublisher
一起绕过代码并将它们添加到列表中。
if
我意识到我可以在一个返回的专用函数中重复我现有的语句bool
并这样做,但有没有更简单的方法?
更新
菜单项的资源 ID 值是连续的,如下所示:
#define ID_PUBLISHERS_DATABASE_EXTRA_FILTER_PUBLISHER 35389
#define ID_PUBLISHERS_DATABASE_EXTRA_FILTER_REGULAR_PIONEER 35390
#define ID_PUBLISHERS_DATABASE_EXTRA_FILTER_NOT_APPOINTED 35391
#define ID_PUBLISHERS_DATABASE_EXTRA_FILTER_MINISTERIAL_SERVANT 35392
#define ID_PUBLISHERS_DATABASE_EXTRA_FILTER_ELDER 35393
#define ID_PUBLISHERS_DATABASE_EXTRA_FILTER_UNBAPTISED_PUBLISHER 35394
#define ID_PUBLISHERS_DATABASE_EXTRA_FILTER_OTHER 35395
但是菜单中确实有一个分隔符。
宏的问题
我想我会在测试项目中尝试宏观想法。我在头文件中插入了这个宏:
#define PROCESSFILTER(id, cond) \
if (m_menuExtraPublisherFilter.GetMenuState(id, MF_BYCOMMAND) == MF_CHECKED) \
{ \
bNoExtraPublisherFilter = false; \
if (cond) \
bAdd = true; \
}
我添加m_menuExtraPublisherFilter
为 a 的CMenu
成员变量CDiialogEx
。然后我创建了只使用标准条件的虚拟资源 ID ID_TEST
,因为我无法访问演示中的工具库。在OnInitDialog
我尝试过:
PROCESSFILTER(ID_TEST, 5 > 4);
但它崩溃了。为什么?