python - Python RegEx 查找接近（之前和/或之后）特定单词的数值

Question

我有一个看起来像这样的字符串：

“ 该公寓自 2021 年起出租给一名学生。每月租金为 850 欧元。额外费用为水电费（150 欧元）。”

我正在寻找与“租”和“欧元”非常接近（例如 20 个字符内）的数值。

我不想得到“2021”，也不想得到“150”——我想得到“850”。

目前我正在使用此代码，但最终得到“2021”。你能帮助我吗？

提前非常感谢！菲利克斯

txt = "The apartment is rented out to a student since 2021. The monthly rent is 850 Euro. Additional costs are utilities (150 Euro)."

txt = ("".join(txt)).strip()

m = re.search(r'(?:((?i:rent)|JNKM)[\w\€\:\(\)\.\!\?\-\\,\ ]{0,40}(\d+[\,\.]?\d*)|(?:(\d+[\,\.]?\d*)[\w\€\:\(\)\.\!\?\-\\,\ ]{0,40}((?i:rent)|JNKM)))',"".join(txt))

txtrent = m.group().replace(".","").replace(",",".")

txtrent = re.findall(r"-?\d+[\,\.]?\d*", txtrent    )

zustand = txtrent

print(zustand)```

Answer 1

看一下这个：

txt = "The apartment is rented out to a student since 2021. The monthly rent is 850 Euro. Additional costs are utilities (150 Euro)."
txt = txt.replace('.', '')

pattern = '\s'
result = re.split(pattern, txt)
txt = result[result.index('rent'): result.index('Euro')+1]
for i in txt:
    if i.isdigit():
        print(i)