我想在两次(多次)ipcRenderer.on()
触发后调用回调函数。我厌倦了这个...
(async () => {
await ipcRenderer.on('all-items-data-fetched', (event, data) => {
itemData = data;
});
await ipcRenderer.on('all-groups-data-fetched', (event, data) => {
data.forEach((el) => {
groupObj[el.id] = el.name;
const option = document.createElement('option');
option.value = el.id;
option.textContent = el.name;
underGroup.appendChild(option);
});
});
})()
.then(() => { console.log(itemData);
dataTable.clear().draw();
itemData.forEach((el) => {
itemNames.push(el.name);
el.groupId = groupObj[el.groupId];
dataTable.row.add(el).draw();
});
table.querySelectorAll('button').forEach((el) => {
el.addEventListener('click', tableActions);
});
});
但不起作用,我希望首先两个 IPC 事件ipcRenderer.on('all-items-data-fetched', (event, data) => {...}
并且ipcRenderer.on('all-groups-data-fetched', (event, data) => {...}
应该触发然后调用回调函数。我怎样才能做到这一点?