17

我想使用具有以下行为/功能的 PopupWindow：

  • 它是可聚焦的（例如按钮内部有交互式控件）
  • View 'under' popupwindow 必须正确消耗弹出窗口之外的触摸
  • ..但即使在外面点击后，弹出窗口也必须留在屏幕上

我发现了一堆关于 PopupWindow 的帖子，但没有人问过如何处理这种情况。

我想我尝试了 setOutsideTouchable()、setFocusable()、setTouchable() 的所有可能组合，但我被卡住了。弹出窗口可以正确处理点击它，但在触摸外部时它总是被解雇。

我当前的代码是： 

View.OnTouchListener customPopUpTouchListenr = new View.OnTouchListener(){

    @Override
    public boolean onTouch(View arg0, MotionEvent arg1) {
        Log.d("POPUP", "Touch false");
        return false;
    }

};


LayoutInflater inflater = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE);
LinearLayout layout= (LinearLayout)inflater.inflate(R.layout.insert_point_dialog, null);
PopupWindow pw = new PopupWindow(layout,400,200,true);
pw.setOutsideTouchable(true);
pw.setTouchable(true);
pw.setBackgroundDrawable(new BitmapDrawable());
pw.setTouchInterceptor(customPopUpTouchListenr);
pw.showAtLocation(frameLayout, Gravity.BOTTOM, 0, 0);

我的总体目标是创建一个浮动窗口，其行为类似于 gimp 等软件中的“工具调色板”：内部有一些控件，保持在顶部直到被“X”按钮关闭，并允许与外部控件交互。也许有一些更好的方法可以做到这一点，而不是 PopupWindow？但是我还没有找到更合适的控件。

4

9 回答 9

10

这里或其他地方没有任何建议似乎对我有用。所以我这样做了：

popupWindow.setTouchInterceptor(new View.OnTouchListener() {
            @Override
            public boolean onTouch(View view, MotionEvent motionEvent) {
                if (motionEvent.getX() < 0 || motionEvent.getX() > viewWidth) return true;
                if (motionEvent.getY() < 0 || motionEvent.getY() > viewHight) return true;

                return false;
            }
        });

如果触摸在 popupWIdow 的范围内，则不消耗触摸事件（因此按钮或滚动视图将起作用）。如果触摸超出范围，则触摸被消耗并且不会传递给 popupWindow，因此不会被关闭。

于 2019-04-10T01:05:08.240 回答
6

为时已晚，但对于谷歌这些东西的人来说只是改变行的顺序

pw.showAtLocation(frameLayout, Gravity.BOTTOM, 0, 0);
pw.setOutsideTouchable(true);
pw.setTouchable(true);
pw.setBackgroundDrawable(new BitmapDrawable());
pw.setTouchInterceptor(customPopUpTouchListenr);

代替

pw.setOutsideTouchable(true);
pw.setTouchable(true);
pw.setBackgroundDrawable(new BitmapDrawable());
pw.setTouchInterceptor(customPopUpTouchListenr);
pw.showAtLocation(frameLayout, Gravity.BOTTOM, 0, 0);

在 showatlocation 方法之后放置任何东西都会让它像什么都没有

于 2013-06-10T12:40:34.010 回答
6

只需删除pw.setBackgroundDrawable(new BitmapDrawable());

于 2012-08-09T06:09:25.593 回答
2

pw.setOutsideTouchable(false);

于 2012-05-02T02:46:41.623 回答
2

尝试

pw.setBackgroundDrawable(null);
于 2012-10-04T08:41:39.667 回答
1

解决方案是：

popupWindow.setFocusable(true);

popupWindow.update();

感谢： http ://android-er.blogspot.ch/2012/04/disable-outside-popupwindow-by.html

于 2014-05-13T08:36:30.100 回答
1

首先，您必须弄清楚为什么当您触摸外部时弹出窗口会被关闭。

看完PopupWindow的源码和资源文件styles.xml，

<style name="Widget.PopupWindow">
    <item name="popupBackground">@drawable/editbox_dropdown_background_dark</item>
    <item name="popupAnimationStyle">@style/Animation.PopupWindow</item>
</style>
 <style name="Widget">
    <item name="textAppearance">?textAppearance</item>
</style>

所以没有什么像对话框主题：

<style name="Theme.Dialog">
<item name="windowCloseOnTouchOutside">@bool/config_closeDialogWhenTouchOutside</item>
</style name="Theme.Dialog">

但是当调用 PopupWindow.setBackgroundDrawable() 时会发生一些事情，

private void preparePopup(WindowManager.LayoutParams p) {
    if (mContentView == null || mContext == null || mWindowManager == null) {
        throw new IllegalStateException("You must specify a valid content view by "
                + "calling setContentView() before attempting to show the popup.");
    }

    if (mBackground != null) {
        final ViewGroup.LayoutParams layoutParams = mContentView.getLayoutParams();
        int height = ViewGroup.LayoutParams.MATCH_PARENT;
        if (layoutParams != null &&
                layoutParams.height == ViewGroup.LayoutParams.WRAP_CONTENT) {
            height = ViewGroup.LayoutParams.WRAP_CONTENT;
        }

        // when a background is available, we embed the content view
        // within another view that owns the background drawable
        PopupViewContainer popupViewContainer = new PopupViewContainer(mContext);
        PopupViewContainer.LayoutParams listParams = new PopupViewContainer.LayoutParams(
                ViewGroup.LayoutParams.MATCH_PARENT, height
        );
        popupViewContainer.setBackgroundDrawable(mBackground);
        popupViewContainer.addView(mContentView, listParams);

        mPopupView = popupViewContainer;
    } else {
        mPopupView = mContentView;
    }
    mPopupViewInitialLayoutDirectionInherited =
            (mPopupView.getRawLayoutDirection() == View.LAYOUT_DIRECTION_INHERIT);
    mPopupWidth = p.width;
    mPopupHeight = p.height;
}

创建了一个容器视图“PopupViewContainer”。

 private class PopupViewContainer extends FrameLayout {
    private static final String TAG = "PopupWindow.PopupViewContainer";

    public PopupViewContainer(Context context) {
        super(context);
    }


    @Override
    public boolean dispatchTouchEvent(MotionEvent ev) {
        if (mTouchInterceptor != null && mTouchInterceptor.onTouch(this, ev)) {
            return true;
        }
        return super.dispatchTouchEvent(ev);
    }

    @Override
    public boolean onTouchEvent(MotionEvent event) {
        final int x = (int) event.getX();
        final int y = (int) event.getY();

        if ((event.getAction() == MotionEvent.ACTION_DOWN)
                && ((x < 0) || (x >= getWidth()) || (y < 0) || (y >= getHeight()))) {
            dismiss();
            return true;
        } else if (event.getAction() == MotionEvent.ACTION_OUTSIDE) {
            dismiss();
            return true;
        } else {
            return super.onTouchEvent(event);
        }
    }

}

现在你知道重要的原因了。因此，有两种方法可以避免在触摸外部后关闭 PopupWindow。1.就像@Raaga 所做的那样。删除 pw.setBackgroundDrawable(new BitmapDrawable());

  1. 您可以实现一个 OnTouchListener 来过滤 PopupWindow 之外的触摸事件。
于 2015-06-02T02:35:35.100 回答
1

有一个非常规的解决方案：重写dismiss来阻止它调用super.dismiss，然后创建一个自定义方法来控制dismiss，这里是示例代码：

class XXXPopupWindow(
    val context: Context
) : PopupWindow() {

    init {
        //some your own logic initialization
        isOutsideTouchable = true
        isTouchable = true
        isFocusable = false
    }


    override fun dismiss() {
        //avoid click outside will dismiss this, use close when want to dismiss this
    }

    fun close(){
        super.dismiss()
    }
}
于 2022-01-04T05:15:17.570 回答
0

可以为 PopupWindow 设置焦点（假）

按钮仍然可以点击，但没有视觉点击行为（一些自定义处理程序强制显示点击？）

下面是带有“始终在顶部”选项的浮动窗口的示例

浮动窗口附近的原始布局在这两种情况下都是完全可操作的，此外，当窗口仍处于浮动状态时，可以使用对话框和其他弹出窗口

窗户也是可重复使用的

final static int buttonAlpha = 0xDF;
final static float buttonTextSize = 12f;

public final void addPopupButton(LinearLayout linearLayout, String title, android.view.View.OnClickListener onClickListener)
{
    Button button = new Button(this.getContext());
    button.setText(title);
    button.setTextSize(buttonTextSize);
    button.getBackground().setAlpha(buttonAlpha);
    button.setOnClickListener(onClickListener);
    linearLayout.addView(button, LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT);
}

public final Button addPopupCheckbox(LinearLayout linearLayout, String title, boolean isChecked, android.view.View.OnClickListener onClickListener)
{
    final Button button = new Button(getContext());
    button.setText(title);
    button.setTextSize(buttonTextSize);
    final int buttonHeight = button.getHeight();
    setButtonChecked(button, isChecked);
    button.setHeight(buttonHeight);
    button.getBackground().setAlpha(buttonAlpha);
    button.setOnClickListener(onClickListener);
    linearLayout.addView(button, LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT);
    return button;
}

public final void setButtonChecked(Button button, boolean isChecked)
{
    button.setCompoundDrawablesWithIntrinsicBounds(Resources.getSystem().getIdentifier(isChecked ? "android:drawable/btn_check_on" : "android:drawable/btn_check_off", null, null), 0, 0, 0);
}

private boolean isMenuAlwaysOnTop = true;
private PopupWindow popupWindowMenuV2 = null;

public final void popupMenuNav2()
{
    if (popupWindowMenuV2 == null)
    {
        // [start] layout

        ScrollView scrollView = new ScrollView(this.getContext());

        final LinearLayout linearLayoutNavigation = new LinearLayout(this.getContext());
        linearLayoutNavigation.setOrientation(LinearLayout.VERTICAL);
        linearLayoutNavigation.setBackgroundColor(0x7FFFFFFF);
        linearLayoutNavigation.setPadding(20, 10, 20, 10);

        scrollView.addView(linearLayoutNavigation, LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT);

        popupWindowMenuV2 = new PopupWindow(this);
        popupWindowMenuV2.setBackgroundDrawable(new BitmapDrawable());
        popupWindowMenuV2.setWidth(WindowManager.LayoutParams.WRAP_CONTENT);
        popupWindowMenuV2.setHeight(WindowManager.LayoutParams.WRAP_CONTENT);
        popupWindowMenuV2.setTouchable(true);
        popupWindowMenuV2.setOutsideTouchable(!isMenuAlwaysOnTop);
        popupWindowMenuV2.setFocusable(!isMenuAlwaysOnTop);
        popupWindowMenuV2.setTouchInterceptor(new OnTouchListener()
        {
            @Override
            public boolean onTouch(View v, MotionEvent event)
            {
                if ((event.getAction() & MotionEvent.ACTION_MASK) == MotionEvent.ACTION_OUTSIDE)
                {
                    if (!isMenuAlwaysOnTop)
                        popupWindowMenuV2.dismiss();
                    else
                        return false;
                    return true;
                }
                return false;
            }
        });
        popupWindowMenuV2.setContentView(scrollView);

        // [end] layout

        // [start] always on top checkbox

        final Button buttonMenuAlwaysOnTop = addPopupCheckbox(linearLayoutNavigation, "always on top", isMenuAlwaysOnTop, null);
        buttonMenuAlwaysOnTop.setOnClickListener(
                new OnClickListener()
                {
                    @Override
                    public void onClick(View vv)
                    {
                        isMenuAlwaysOnTop = !isMenuAlwaysOnTop;
                        setButtonChecked(buttonMenuAlwaysOnTop, isMenuAlwaysOnTop);
                        popupWindowMenuV2.dismiss();
                        popupWindowMenuV2.setOutsideTouchable(!isMenuAlwaysOnTop);
                        popupWindowMenuV2.setFocusable(!isMenuAlwaysOnTop);
                        popupWindowMenuV2.showAtLocation(((Activity) getContext()).getWindow().getDecorView(), Gravity.CENTER_VERTICAL + Gravity.RIGHT, 0, 0);
                    }
                });

        // [end] always on top checkbox

        addPopupButton(linearLayoutNavigation, "some button",
                new OnClickListener()
                {
                    @Override
                    public void onClick(View vv)
                    {
                        if (!isMenuAlwaysOnTop)
                            popupWindowMenuV2.dismiss();
                        someAction();
                    }
                });

    }

    popupWindowMenuV2.showAtLocation(((Activity) getContext()).getWindow().getDecorView(), Gravity.CENTER_VERTICAL + Gravity.RIGHT, 0, 0);
}

// somewhere in handler:
            if (someCondition)
            {
                if (popupWindowMenuV2 != null && popupWindowMenuV2.isShowing())
                    popupWindowMenuV2.dismiss();
                else
                    popupMenuNav2();
                return true;
            }
于 2014-03-26T21:39:29.387 回答