python - Starlette JSONResponse 到 Pydantic parse_obj_as

Question

使用 fastapi 并拥有一个返回创建的 JSONResponse 的函数。我的目标是创建自定义的 200 响应并将其放入 Pydanticparse_obj_as中并带有预期的 BaseModel。

有没有办法取回 JSONResponse 数据？或者有什么解决办法？谢谢！

from starlette.responses import JSONResponse


def func():
    model_id = 0

    resp = JSONResponse(
        {"detail": f"Model {model_id} created", "HTTPStatusCode": 200},
       status_code=200,
    )
    return parse_obj_as(<here I need resp data>, MyBaseModel)

基本型号：

from pydantic.types import PositiveInt
from __future__ import annotations, generator_stop
from pydantic import BaseModel

class MyBaseModel(BaseModel):
    """
    Docstring
    """

    detail: str
    HTTPStatusCode: PositiveInt

Answer 1

parse_obj_as需要字典输入。响应对象的主体可通过 访问response.body。并且您需要通过调用将字节类型的正文转换为字典json.loads()。

import json
from pydantic.types import PositiveInt
from starlette.responses import JSONResponse
from pydantic import BaseModel, parse_obj_as


class MyBaseModel(BaseModel):
    """
    Docstring
    """
    detail: str
    HTTPStatusCode: PositiveInt


def func():
    model_id = 0
    resp = JSONResponse(
        {"detail": f"Model {model_id} created", "HTTPStatusCode": 200}, status_code=200,
    )
    return parse_obj_as(MyBaseModel, json.loads(resp.body))


ret = func()

这是返回值：

detail='Model 0 created' HTTPStatusCode=200