1

又是我和我的 BlockingQueue……我根据这篇文章这个问题重写了它。它发送一些项目,然后因访问冲突而崩溃。这是代码:

template <typename T>
bool DRA::CommonCpp::CTBlockingQueue<T>::Push( T pNewValue ){
    volatile long oldSize;
    ::InterlockedExchange( &oldSize, m_Size );
    CTNode* pNewNode = new CTNode();
    pNewNode->m_pValue = pNewValue;
    {//RAII block
        CGuard g( m_TailCriticalSection );
        m_pTailNode->m_pNext = pNewNode;
        m_pTailNode = pNewNode;
        ::InterlockedIncrement( &m_Size );
    }
    if( oldSize == 0 )
        m_eAtLeastOneElement.set();
    return true;
}

template <typename T>
bool DRA::CommonCpp::CTBlockingQueue<T>::Pop( T& pValue ){
    CTNode* pCurrentNode;
    {//RAII block
        CGuard g( m_HeadCriticalSection );
        pCurrentNode = m_pHeadNode;
        CTNode* pNewHeadNode = m_pHeadNode->m_pNext;
        if( pNewHeadNode == NULL ){
            CEvent* pSignaledEvent;
            CEvent::waitForPair( m_eAtLeastOneElement, m_eFinished, pSignaledEvent );
            if( pSignaledEvent == &m_eFinished )
                return false;
            pNewHeadNode = m_pHeadNode->m_pNext;
        }
        pValue = pNewHeadNode->m_pValue;
        m_pHeadNode = pNewHeadNode;
        ::InterlockedDecrement( &m_Size );
    }
    delete pCurrentNode;
    return true;
}

它总是在对 Pop() 的调用中崩溃,在 if 之后的行中,它说:

pValue = pNewHeadNode->m_pValue

它炸毁了 cos 的 pNewHeadNode 为 NULL。但这怎么会发生呢?

编辑:忘记初始化代码:

template <typename T>
DRA::CommonCpp::CTBlockingQueue<T>::CTBlockingQueue():
        m_HeadCriticalSection("CTBlockingQueue<T>::m_Head"),
        m_TailCriticalSection("CTBlockingQueue<T>::m_Tail"){
    CTNode* pDummyNode = new CTNode();
    m_pHeadNode = pDummyNode;
    m_pTailNode = pDummyNode;
    m_Size = 0; //Dummy node doesn't count
}
4

2 回答 2

1

我的假设必须是事件设置在关键部分之外,这意味着推送可能会两次通知事件。您是否尝试过在关键部分内设置事件?

于 2011-07-14T18:15:19.447 回答
0

最后,我回到了我原来的效率较低的实现,我在这里发布的那个,添加了一个 Finish() 方法,以便生产者可以通知消费者优雅地结束,以及一个 Restart() 方法开始在不破坏和重新创建队列的情况下再次生产:

//Template definitions
template<class Element>
DRA::CommonCpp::CTBlockingQueue<Element>::CTBlockingQueue( unsigned int maxSize ):
    m_csFinished( "CTBlockingQueue::m_csFinished" ),
    m_csQueue( "CTBlockingQueue::m_csQueue" ),
    m_semElementCount( 0, maxSize ),
    m_bFinished(false){
}

template<class Element>
DRA::CommonCpp::CTBlockingQueue<Element>::~CTBlockingQueue(){
    Finish();
}

template<class Element>
void DRA::CommonCpp::CTBlockingQueue<Element>::Push( Element newElement ){
    {//RAII block
        CGuard g( m_csQueue );
        m_Queue.push( newElement );
    }
    m_semElementCount.Signal();
}

template<class Element>
bool DRA::CommonCpp::CTBlockingQueue<Element>::Pop( Element& element ){
    m_semElementCount.Wait();
    {//RAII block
        CGuard g( m_csFinished );
        if( m_bFinished ){
            CGuard g( m_csQueue );
            if ( m_Queue.size() == 0 )
                return false;
        }
    }
    {//RAII block
        CGuard g( m_csQueue );
        element = m_Queue.front();
        m_Queue.pop();
    }
    return true;
}

template<class Element>
void DRA::CommonCpp::CTBlockingQueue<Element>::Finish(){
    {//RAII block
        CGuard g( m_csFinished );
        m_bFinished = true;
    }
    {//RAII block
        CGuard g( m_csQueue );
        m_semElementCount.Signal();
    }
}

template<class Element>
void DRA::CommonCpp::CTBlockingQueue<Element>::Restart(){
    {//RAII block
        CGuard g( m_csFinished );
        m_bFinished = false;
    }
}

这不是最快的方法,但对我来说足够快。

于 2011-07-26T12:55:28.607 回答