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我是颤振和火力的新手。

我有一个名为“dishes”的集合,其中有许多文档(例如名称、描述等),我还有一个名为 components 的子集合,其中包含 id、名称和数量作为文档。

我正在尝试做的是检索所有带有配料的菜肴。

我有菜模型

class DishModel{
  static const ID = "id";
  static const DESCRIPTION = "description";
  static const IMAGE = "image";
  static const NAME = "name";
  static const INGREDIENTS = "ingredients";

  int _id;
  String _description;
  String _image;
  String _name;
  double _price;
  int _rates;
  double _rating;
  List<IngredientModel> _ingredients;

//GETTERS

  int get id => _id;

  String get description => _description;


  String get image => _image;



  String get name => _name;

  List<IngredientModel> get ingredients => _ingredients;

  DishModel.fromSnapshot(DocumentSnapshot snapshot){
    _id = snapshot.data()[ID];
    _description = snapshot.data()[DESCRIPTION];
    _image = snapshot.data()[IMAGE];
    _name = snapshot.data()[NAME];
  }
}

成分模型

class IngredientModel{
  static const ID = "id";
  static const NAME = "name";
  static const QUANTITY = "quantity";

  int _id;
  String _name;
  String _quantity;

  //GETTERS

  int get id => _id;

  String get name => _name;

  String get quantity => _quantity;


  IngredientModel.fromSnapshot(DocumentSnapshot snapshot){
    _id = snapshot.data()[ID];
    _name = snapshot.data()[NAME];
    _quantity = snapshot.data()[QUANTITY];

  }


}

餐具帮手

class DishServices{
  String collection = "dishes";
  FirebaseFirestore _firestore = FirebaseFirestore.instance;
  String subcollection = "ingredients";

  Future<List<DishModel>> getDishes() async
  {
    DishModel dishTemp ;
    List<DishModel> dishes = [];
    _firestore.collection(collection).get().then((result) {
      for (DocumentSnapshot dish in result.docs) {
        dishTemp = DishModel.fromSnapshot(dish);
        dish.reference.collection(subcollection).get().then((ingredientRes) {
          for(DocumentSnapshot ingredient in ingredientRes.docs) {
            dishTemp.ingredients.add(IngredientModel.fromSnapshot(ingredient));
          }
        });
        dishes.add(dishTemp);
      }
      return dishes;
    });

  }

}

DishProvider

class DishProvider with ChangeNotifier{
  DishServices _dishServices = DishServices();
  List<DishModel> dishes = [];

  DishProvider.initialize(){
    _loadDishes();
  }

  _loadDishes() async{
    dishes = await _dishServices.getDishes();
    notifyListeners();
  }


}

我主要写了

 runApp(MultiProvider(providers: [
    ChangeNotifierProvider.value(value: DishProvider.initialize())
  ],
      child: MaterialApp(
          debugShowCheckedModeBanner: false,
          title: 'example_app',
          theme: ThemeData(
            primarySwatch: Colors.red,
          ),
          home: ScreensController()
      )));
}

在家里(在构建方法中)

final dishProvider =  Provider.of<DishProvider>(context);

但是如果我尝试打印print(dishProvider.dishes);,我会得到flutter: null而不是颤动:Instance of 'DishModel'

我该如何解决它并检索我的菜肴信息?

谢谢你们

4

3 回答 3

1

您需要获取菜品文档的 id 来检索子集合。

FirebaseFirestore.instance
              .collection('dishes')
              .doc(docId)
              .collection('ingredients')
              .snapshots(),

是一个 Github 仓库

于 2021-04-01T16:30:26.360 回答
0

getDishes()我认为循环中有一些东西。这就是文档扔数据的方式:

FirebaseFirestore.instance
    .collection('users')
    .get()
    .then((QuerySnapshot querySnapshot) {
        querySnapshot.docs.forEach((doc) {
            print(doc["first_name"]);
        });
    });

按照文档:https : //firebase.flutter.dev/docs/firestore/usage 你能尝试使用forEach吗?

于 2021-04-01T14:28:06.880 回答
0

我发现了错误,它在 getDishes 方法中,正确的是:

Future<List<DishModel>> getDishes() async
  {
    DishModel dishTemp ;
    List<DishModel> dishes = [];
    _firestore.collection(collection).get().then((result) {
      for (DocumentSnapshot dish in result.docs) {
        dishTemp = DishModel.fromSnapshot(dish);
        List<IngredientModel> ing_temp = [];
        dish.reference.collection(subcollection).get().then((ingredientRes) {
          for(DocumentSnapshot ingredient in ingredientRes.docs) {
            ing_temp.add(IngredientModel.fromSnapshot(ingredient));

          }
          dishTemp.ingredients = ing_temp;
        });
        dishes.add(dishTemp);
      }
      return dishes;
    });
    return dishes;
  }

谢谢大家

于 2021-04-02T09:54:18.057 回答