4

我正在尝试一起实现通用规范模式和通用访问者模式。这是我的基本接口。

export interface Specification<T, TVisitor extends SpecificationVisitor<TVisitor, T>> {
  accept(visitor: TVisitor): void;
  isSatisfiedBy(candidate: T): boolean;
  and(other: Specification<T, TVisitor>): Specification<T, TVisitor>;
  andNot(other: Specification<T, TVisitor>): Specification<T, TVisitor>;
  or(other: Specification<T, TVisitor>): Specification<T, TVisitor>;
  orNot(other: Specification<T, TVisitor>): Specification<T, TVisitor>;
  not(): Specification<T, TVisitor>;
}

export interface SpecificationVisitor<TVisitor extends SpecificationVisitor<TVisitor, T>, T> {
  visit(specification: AndSpecification<T, TVisitor>): void;
  visit(specification: AndNotSpecification<T, TVisitor>): void;
  visit(specification: OrSpecification<T, TVisitor>): void;
  visit(specification: OrNotSpecification<T, TVisitor>): void;
  visit(specification: NotSpecification<T, TVisitor>): void;
}

为方便起见，我为基本布尔运算符实现了一些基类和一个抽象类。

export abstract class CompositeSpecification<T, TVisitor extends SpecificationVisitor<TVisitor, T>> implements Specification<T, TVisitor> {
  abstract isSatisfiedBy(candidate: T): boolean;
  abstract accept(visitor: TVisitor): void;

  and(other: Specification<T, TVisitor>): Specification<T, TVisitor> {
    return new AndSpecification<T, TVisitor>(this, other);
  }
  andNot(other: Specification<T, TVisitor>): Specification<T, TVisitor> {
    return new AndNotSpecification<T, TVisitor>(this, other);
  }
  or(other: Specification<T, TVisitor>): Specification<T, TVisitor> {
    return new OrSpecification<T, TVisitor>(this, other);
  }
  orNot(other: Specification<T, TVisitor>): Specification<T, TVisitor> {
    return new OrNotSpecification<T, TVisitor>(this, other);
  }
  not(): Specification<T, TVisitor> {
    return new NotSpecification<T, TVisitor>(this);
  }
}

export class AndSpecification<T, TVisitor extends SpecificationVisitor<TVisitor, T>> extends CompositeSpecification<
  T,
  TVisitor
> {
  constructor(readonly left: Specification<T, TVisitor>, readonly right: Specification<T, TVisitor>) {
    super();
  }

  accept(visitor: TVisitor): void {
    visitor.visit(this);
  }

  isSatisfiedBy(candidate: T): boolean {
    return this.left.isSatisfiedBy(candidate) && this.right.isSatisfiedBy(candidate);
  }
}

export class AndNotSpecification<T, TVisitor extends SpecificationVisitor<TVisitor, T>> extends CompositeSpecification<T, TVisitor> {
  constructor(readonly left: Specification<T, TVisitor>, readonly right: Specification<T, TVisitor>) {
    super();
  }

  accept(visitor: TVisitor): void {
    visitor.visit(this);
  }

  isSatisfiedBy(candidate: T): boolean {
    return this.left.isSatisfiedBy(candidate) && !this.right.isSatisfiedBy(candidate);
  }
}

export class OrSpecification<T, TVisitor extends SpecificationVisitor<TVisitor, T>> extends CompositeSpecification<
  T,
  TVisitor
> {
  constructor(readonly left: Specification<T, TVisitor>, readonly right: Specification<T, TVisitor>) {
    super();
  }

  accept(visitor: TVisitor): void {
    visitor.visit(this);
  }

  isSatisfiedBy(candidate: T): boolean {
    return this.left.isSatisfiedBy(candidate) || this.right.isSatisfiedBy(candidate);
  }
}

export class OrNotSpecification<T, TVisitor extends SpecificationVisitor<TVisitor, T>> extends CompositeSpecification<
  T,
  TVisitor
> {
  constructor(readonly left: Specification<T, TVisitor>, readonly right: Specification<T, TVisitor>) {
    super();
  }

  accept(visitor: TVisitor): void {
    visitor.visit(this);
  }

  isSatisfiedBy(candidate: T): boolean {
    return this.left.isSatisfiedBy(candidate) || !this.right.isSatisfiedBy(candidate);
  }
}

export class NotSpecification<T, TVisitor extends SpecificationVisitor<TVisitor, T>> extends CompositeSpecification<
  T,
  TVisitor
> {
  constructor(readonly other: Specification<T, TVisitor>) {
    super();
  }

  accept(visitor: TVisitor): void {
    visitor.visit(this);
  }

  isSatisfiedBy(candidate: T): boolean {
    return !this.other.isSatisfiedBy(candidate);
  }
}

所有上述工作和编译没有错误。但是当我尝试创建一个扩展基本 SpecificationVisitor 接口的接口并实现一个扩展抽象 CompositeSpecification 的类时遇到编译器问题。

export interface NumberComparatorVisitor extends SpecificationVisitor<NumberComparatorVisitor, number> {
  visit(specification: GreaterThan): void;
}

export class GreaterThan extends CompositeSpecification<number, NumberComparatorVisitor> {
  constructor(readonly value: number) {
    super();
  }

  accept(visitor: NumberComparatorVisitor): void {
    visitor.visit(this);
  }

  isSatisfiedBy(candidate: number): boolean {
    return candidate > this.value;
  }
}

我收到以下错误：

Type 'NumberComparatorVisitor' does not satisfy the constraint 'SpecificationVisitor<NumberComparatorVisitor, number>'.ts(2344)

Interface 'NumberComparatorVisitor' incorrectly extends interface 'SpecificationVisitor<NumberComparatorVisitor, number>'.
  Types of property 'visit' are incompatible.
    Type '(specification: GreaterThan) => void' is not assignable to type '{ (specification: AndSpecification<number, NumberComparatorVisitor>): void; (specification: AndNotSpecification<number, NumberComparatorVisitor>): void; (specification: OrSpecification<...>): void; (specification: OrNotSpecification<...>): void; (specification: NotSpecification<...>): void; }'.
      Types of parameters 'specification' and 'specification' are incompatible.
        Type 'AndSpecification<number, NumberComparatorVisitor>' is not assignable to type 'GreaterThan'.ts(2430)

Type 'NumberComparatorVisitor' does not satisfy the constraint 'SpecificationVisitor<NumberComparatorVisitor, number>'.
  Types of property 'visit' are incompatible.
    Type '(specification: GreaterThan) => void' is not assignable to type '{ (specification: AndSpecification<number, NumberComparatorVisitor>): void; (specification: AndNotSpecification<number, NumberComparatorVisitor>): void; (specification: OrSpecification<...>): void; (specification: OrNotSpecification<...>): void; (specification: NotSpecification<...>): void; }'.
      Types of parameters 'specification' and 'specification' are incompatible.
        Property 'value' is missing in type 'AndSpecification<number, NumberComparatorVisitor>' but required in type 'GreaterThan'.ts(2344)

我不太明白它为什么抱怨。我需要改变什么才能让它按照我想要的方式工作？

4

1 回答 1

5

哇，里面有很多代码。让我们将其缩减为一个显示相同问题的最小可重现示例：

interface Foo {
  ovld(x: string): number;
  ovld(x: number): boolean;
}

interface BadBar extends Foo {  // error!
  ovld(x: boolean): string;
}

在这里，您有一个Foo带有重载方法的接口，名为ovld. 该方法有两个调用签名；一个需要 a string，另一个需要 a number。我们尝试制作BadBar扩展它的接口。我们的目的是添加第三个重载，ovld它需要一个boolean. 但它不起作用！为什么？

答案是在扩展接口时不能简单地添加重载。接口扩展不是 接口合并。通过在扩展接口中重新声明，您是在告诉编译器用 in的版本ovld完全覆盖 in 的ovld类型。并且因为 in 中的单个调用签名不能分配给 in 中的调用签名，所以这是一个错误，就像这是一个错误：FooBadBarBadBarFoo

interface XXX {
  prop: string;
}
interface YYY extends XXX { // error!
  prop: boolean; 
}

在这两种情况下，您都通过采用现有属性或方法并进行无效更改来错误地扩展接口。唯一可接受的更改是缩小更改，例如将 a 更改string为"a" | "b".

那么，如果我们不能仅仅通过重新声明ovld()in来BadBar添加重载，我们该怎么做呢？一种方法是使用索引访问类型从父接口获取现有调用签名，然后将其与新调用签名相交：

interface GoodBar extends Foo {
  ovld: ((x: boolean) => string) & Foo["ovld"]
} 
/* (property) GoodBar.ovld: ((x: boolean) => string) & {
  (x: string): number;
  (x: number): boolean;
} */

交集X & Y将被视为 的有效缩小X，因此编译器错误消失。此外，TypeScript 认为函数的交集等同于重载。因此，上面为您提供了新的(x: boolean) => string调用签名作为第一个重载，然后是现有的两个重载签名Foo：

declare const goodBar: GoodBar;
goodBar.ovld(false).toUpperCase();
goodBar.ovld("hello").toFixed();
goodBar.ovld(123) === true;

万岁！

这意味着您NumberComparatorVisitor可能需要更改为以下内容：

export interface NumberComparatorVisitor extends
  SpecificationVisitor<NumberComparatorVisitor, number> {
  visit: (
    ((specification: GreaterThan) => void) &
    SpecificationVisitor<NumberComparatorVisitor, number>["visit"]
  );
}

如果我进行更改，那么错误就会消失，因为 nowNumberComparatorVisitor确实是其父接口的有效扩展。

Playground 代码链接

于 2021-03-24T03:47:54.320 回答