我正在使用 Python 2.5 编写一个 TkInter 应用程序,我需要找出大写锁定和 shift 键的状态(真或假)。我已经搜索了整个网络,但找不到解决方案。
Victor
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4 回答
3
Tkinter 中的键盘事件可能很棘手。
我建议您按顺序查看以下内容:
- http://effbot.org/tkinterbook/tkinter-events-and-bindings.htm
- http://infohost.nmt.edu/tcc/help/pubs/tkinter/events.html(阅读有关事件的整章)
- http://www.faqts.com/knowledge_base/view.phtml/aid/4281
这是一个显示 keycode 和 state 事件参数值的程序。你可以用它来做实验。单击窗口,然后敲击键盘。
from Tkinter import *
root = Tk()
def key(event):
print "Keycode:", event.keycode, "State:", event.state
def callback(event):
frame.focus_set()
print "clicked at", event.x, event.y
frame = Frame(root, width=100, height=100)
frame.bind("<Key>", key)
frame.bind("<Button-1>", callback)
frame.pack()
root.mainloop()
于 2009-03-20T10:16:34.457 回答
1
Lock
和Shift
事件修饰符:
http://infohost.nmt.edu/tcc/help/pubs/tkinter/event-modifiers.html
于 2009-03-20T10:08:20.843 回答
0
我用谷歌搜索了一个..我不确定它是否适用于所有键...
http://www.java2s.com/Code/Python/Event/KeyactionFunctionKeyALtControlShift.htm
于 2009-03-20T10:11:50.380 回答
0
利用:
from Tkinter import *
root = Tk()
caps_lock_on = False
def CAPSLOCK_STATE():
import ctypes
hllDll = ctypes.WinDLL ("User32.dll")
VK_CAPITAL = 0x14
return hllDll.GetKeyState(VK_CAPITAL)
CAPSLOCK = CAPSLOCK_STATE()
if ((CAPSLOCK) & 0xffff) != 0:
print "\nCaps lock is on\n"
caps_key_on = True
else:
caps_key_on = False
print 'Caps lock is off'
def caps_lock_pressed(event=''):
global caps_lock_on
if caps_lock_on == False:
caps_lock_on = True
print 'Caps lock is on'
else:
caps_lock_on = False
print 'Caps lock is off'
#Changes if shift key is on and off
def shift_key_pressed(event=''):
global shift_key_on
shift_key_on = True
print 'Shift is being holded'
def shift_key_released(event=''):
global shift_key_on
shift_key_on = False
print 'Shift has been released'
root.bind('<Caps_Lock>',caps_lock_pressed)
root.bind('<Shift_L>',shift_key_pressed)
root.bind('<Shift_R>',shift_key_pressed)
root.bind('<KeyRelease-Shift_R>',shift_key_released)
root.bind('<KeyRelease-Shift_L>',shift_key_released)
root.mainloop()
这将检查它的大写锁定,然后它将绑定大写锁定并转换以更改状态。大写锁定检测系统是借用的。
于 2020-11-02T17:13:19.907 回答