我有一个以编程方式打开的微调器。它弹出并且似乎工作正常,但由于某种原因,我的 OnItemSelectedListener 没有触发其中的任何事件。
public class BeerConverter extends Activity {
ArrayAdapter<CharSequence> adapter3;
Spinner spinner03;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
spinner03 = new Spinner(this);
adapter3 = new ArrayAdapter<CharSequence> (this, android.R.layout.simple_spinner_item);
adapter3.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spinner03.setAdapter(adapter3);
spinner03.setOnItemSelectedListener(new MyOnItemSelectedListener3());
adapter3.add("Stuff");
spinner03.performClick();
}
然后我将侦听器创建为嵌套类:
public class MyOnItemSelectedListener3 implements OnItemSelectedListener {
public void onItemSelected(AdapterView<?> parentview, View v,int position, long id){
curPos = position;
Context context = getApplicationContext();
CharSequence text = "Test text. If you see this, it means MyOnItemSelectedListener3 was called.";
int duration = Toast.LENGTH_SHORT;
Toast toast = Toast.makeText(context, text, duration);
toast.show();
}
public void onNothingSelected(AdapterView<?> arg0)
{
//do nothing
}
};
所以当我发送spinner03.performClick();
Spinner 时会正确弹出,但是当 Spinner 中的一个项目被选中时,它只会关闭并且不会调用 OnItemSelectedListener。看起来这个人不久前遇到了同样的问题,但最终没有发布解决方案。