我有下表包含一个 XML 列：
| ID | 标签 | 细节 |
|---|---|---|
| 1 | 测试1 | <terms><destination><email>email11@foo.com</email><email>email12@foo.com</email></destination><content>blabla</content></terms> |
| 2 | 测试2 | <terms><destination><email>email21@foo.com</email><email>email22@foo.com</email></destination><content>blabla</content></terms> |
我想要一个产生以下输出的查询：
| ID | 标签 | 目的地 |
|---|---|---|
| 1 | 测试1 | email11@foo.com, email12@foo.com |
| 2 | 测试2 | email21@foo.com, email22@foo.com |
关于如何将 XML 电子邮件节点值连接为相关列（Id 和 Label）的列的任何线索？提前谢谢
请尝试以下解决方案。
因为没有提供 DDL 和样本数据填充，所以假设Details列是 XML 数据类型。
SQL
-- DDL and sample data population, start
DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, Label VARCHAR(20), Details XML);
INSERT INTO @tbl (Label, Details) VALUES
('Test1',N'<terms><destination><email>email11@foo.com</email><email>email12@foo.com</email></destination><content>blabla</content></terms>'),
('Test2',N'<terms><destination><email>email21@foo.com</email><email>email22@foo.com</email></destination><content>blabla</content></terms>');
-- DDL and sample data population, end
SELECT ID, Label
, REPLACE(Details.query('data(/terms/destination/email/text())').value('.','VARCHAR(MAX)'), SPACE(1), ', ') AS Destination
FROM @tbl;
输出
+----+-------+----------------------------------+
| ID | Label | Destination |
+----+-------+----------------------------------+
| 1 | Test1 | email11@foo.com, email12@foo.com |
| 2 | Test2 | email21@foo.com, email22@foo.com |
+----+-------+----------------------------------+
select ID, Label,
stuff(
details.query('for $step in /terms/destination/email/text() return concat(", ", string($step))')
.value('.', 'nvarchar(max)'),
1, 2, '')
from @tbl;