2

我有这个函数，它可以在我的机器上使用 python 3.8 在本地正常工作，但它会在 Google Cloud Functions 上引发运行时错误。

def telegram_test(request):
    request_json = request.get_json()
    import datetime
    import pandas as pd
    from pyrogram import Client
    
    session_string = "...............38Q8uTHG5gHwyWD8nW6h................."
    # the rest of the authantication
    api_id = 32494131641215
    api_hash = "ioadsfsjnjksfgnfriuthg#qw]/zwq  ]w/\lc ec,"

    # one of bbc channels on telegram you want to access
    channel_name = 'pyrogram'

    # if you only want to get messages older than 7 days in unix style
    seven_days = int((datetime.datetime.now() - datetime.timedelta(days=7)).timestamp())
    # call telegram with parameters such as limit and date
    # save the result to dataframe

    with Client(session_string,api_id,api_hash, takeout=True,workers=2) as app:
        hist_iter = app.iter_history(channel_name,offset_date=seven_days, limit=100)    
        msglist = [msg.__dict__ for msg in hist_iter]
        df = pd.DataFrame(msglist)
        print(df.head(5))
 
    return f'it works!:{request_json}'

我从 GCF 日志中得到的错误消息：

文件“/opt/python3.8/lib/python3.8/asyncio/events.py”，第 639 行，在 get_event_loop 中引发 RuntimeError('There is no current event loop in thread %r.' RuntimeError: There is no current event在线程“ThreadPoolExecutor-0_0”中循环。

更新

我更新了代码，运行时错误消失了。但我收到超时错误。我将超时设置为 180 秒，但当我测试该功能时仍然超时 60 秒。

这是更新的代码。有什么我做错了吗？

async def foo():
    from datetime import datetime, timedelta
    from pandas import DataFrame
    from pyrogram import Client
    import asyncio

    session_string = "********zNmkubA4ibjsdjhsdfjlhweruifnjkldfioY5DE*********"    
    api_id = 325511548224831351
    api_hash = "jdffjgtrkjhfklmrtgjtrm;sesews;;wex"        
    channel_name = 'cnn'

    with Client(session_string, api_id, api_hash, takeout=True) as app:
        hist_iter = app.iter_history(
            channel_name, limit=10)
        msglist = [msg.__dict__ for msg in hist_iter]
        df = DataFrame(msglist)    
    return df
 
async def bar():
    return await foo() 

def test(request):
    from asyncio import run
    return run(bar())
4

2 回答 2

3

最终的解决方案是从 Pyrogram 更改为 Telethon，并在创建客户端之前手动创建 asyncio。

loop = asyncio.new_event_loop()
asyncio.set_event_loop(loop)
于 2021-02-09T13:34:32.190 回答
1
  1. bar() is redundant
  2. You're trying to return a dataframe. Is it a valid HTTP response?
  3. with -> async with
  4. hist_iter = app.iter_history() -> hist_iter = await app.iter_history()
  5. M.b. it waits for input? enter image description here
于 2021-02-08T07:44:46.767 回答