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我尝试通过 WebClient 从另一个微服务中检索页面。如果我直接向 Postman 请求这个 MS,我会content在页面内部获得“类型”等内容。但是,如果我通过 请求 MS webClient,“类型”将从content(以及其他一些字段)中消失。内容是一个抽象类列表,account“类型”为JsonSubTypes
有人可以找到错误,为什么是“类型”-attrib。消失?

回应

来自的回应http://localhost:8080/api/v1/accounts

{
    "content": [
        {
            "type": "savingsBook",
            "id": 108,
            "accountNumber": 99781944,
            ...
        }
    ], "pageable": {
        ...
    }, "totalPages": ...
    ...
}
    

来自的回应http://localhost:8081/accounts

{
    "content": [
        {
            "id": 108,
            "accountNumber": 99781944,
            ...
        }
    ], "pageable": {
        ...
    }, "totalPages": ...
    ...
}

代码片段:

8080的账户控制器

@RequestMapping(method = RequestMethod.GET, produces = "application/json")
public <T extends Account> Page<T> getAccounts(@RequestParam(value = "page", required = false) Integer page, @RequestParam(value = "pageSize", required = false) Integer pageSize, @RequestParam(value = "sortBy", required = false) String sortBy) {
    if (page == null) {
        page = 0;
    }
    if (pageSize == null) {
        pageSize = 10;
    }
    if (sortBy == null) {
        Page<T> p = accountService.getAccounts(page, pageSize);
        return new PageImpl<T>(p.getContent(), p.getPageable(), p.getTotalElements()) {};

    } else {
        Sort sort = Sort.by(sortBy);
        Page<T> p = accountService.getAccounts(page, pageSize, sort);
        return new PageImpl<T>(p.getContent(), p.getPageable(), p.getTotalElements()) {};
    }
}

8081 帐户控制员

@GetMapping
public  <T extends Account> Page<T> getAllAccounts(@RequestParam(value = "page", required = false) Integer page, 
                                                   @RequestParam(value = "pageSize", required = false) Integer pageSize,
                                                   @RequestParam(value = "sortBy", required = false) String sortBy) {   
     if (page == null) {
         page = 0;
     }
     if (pageSize == null) {
         pageSize = 10;
     }
     if (sortBy == null) {
         return accountService.getAllAccounts(page, pageSize);
     } else {
         return accountService.getAllAccounts(page, pageSize, sortBy);
     }
}

8081 账户服务

public <T extends Account> Page<T> getAllAccounts(Integer pageNumber, Integer pageSize) {
    ParameterizedTypeReference<CustomPageImpl<T>> typeReference = new ParameterizedTypeReference<CustomPageImpl<T>>(){};
    System.out.println("Anfrage an: " + addr + "/accounts/");
    System.out.println(client.get().uri("/accounts/").retrieve().bodyToMono(typeReference).block().getContent());
    Page<T> prodData = (CustomPageImpl<T>)(client.get().uri("/accounts/").retrieve().bodyToMono(typeReference).block());
    return prodData;
}

CustomPageImpl(从另一个 StackOverflow-Post 获得)

public class CustomPageImpl<T> extends PageImpl<T> {
    private static final long serialVersionUID = 1L;

    @JsonCreator(mode = JsonCreator.Mode.PROPERTIES)
    public CustomPageImpl(@JsonProperty("content") List<T> content,
            @JsonProperty("number") int number,
            @JsonProperty("size") int size,
            @JsonProperty("totalElements") Long totalElements,
            @JsonProperty("pageable") JsonNode pageable,
            @JsonProperty("last") boolean last,
            @JsonProperty("totalPages") int totalPages,
            @JsonProperty("sort") JsonNode sort,
            @JsonProperty("first") boolean first,
            @JsonProperty("numberOfElements") int numberOfElements){
        super(content, PageRequest.of(number, size) , totalElements);
    }
    public CustomPageImpl(List<T> content, Pageable pageable, long total) {
        super(content, pageable, total);
    }

    public CustomPageImpl(List<T> content) {
        super(content);
    }

    public CustomPageImpl() {
        super(new ArrayList<>());
    }
}
    
4

1 回答 1

2

我自己找到了这个问题的答案。

问题在于,Account 是抽象的并且具有 json 子类型。public class CustomPageImpl<T> extends PageImpl<T>通过替换public class CustomPageImpl<T extends Account> extends PageImpl<T>我能够解决这个问题。现在我按计划收到了类型。

于 2021-01-19T15:40:26.003 回答