我正在尝试通过下面的这个 sql Select 语句,但我做错了。
Select DISTINCT vc.cid, vt.tid, vc.device,
STUFF((select ', ' + c.tName from thumbTbl t2
join tags v ON t2.cid = v.cid
join config c on v.tid = c.tid
where vc.cid = t2.cid
group by c.tName
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(max)'), 1, 1, '') tName
from tags vt
Inner join thumbTbl vc on vt.cid = vc.cid
Left join config vtc on vt.tid = vtc.tid
order by vc.cid asc
结果如下:
cid tid device tName
--- --- --------- ---------
159 7 Mat Dwens Escalation, Follow Up, More Benefits
159 11 Mat Dwens Escalation, Follow Up, More Benefits
159 12 Mat Dwens Escalation, Follow Up, More Benefits
160 7 Jeniffer P Rectro
162 8 Marc Novice More Benefits, Rectro
162 6 Marc Novice More Benefits, Rectro
165 4 Jeniffer P Follow up
问题:如何仅显示每个 Selected Id 的 1 行?,我尝试使用SELECT DISTINCT但仍然给了我与以上相同的结果。
我想看到的结果必须如下所示:
cid tid device tName
------- --------- ----------
159 12 Mat Dwens Escalation, Follow Up, More Benefits
160 7 Jeniffer P Rectro
162 8 Marc Novice More Benefits, Rectro
165 4 Jeniffer P Follow up
有人有想法吗?