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我正在尝试路由到单个类并在该类中加载不同的方法。现在我只能设法handle()在SearchInquiryHandler课堂内加载。我怎样才能从不同的路线加载loadThisMethod()内部。SearchInquiryHandler我在想我是否可以检测到路由 url，并且通过适当的检查，我可以loadThisMethod()从我的handle()方法中加载。任何指导都会非常有帮助。

对于一条路线，这里是routes.php

return static function (Application $app, MiddlewareFactory $factory, ContainerInterface $container) : void {

    $app->post('/api/search/inquiry', App\Handler\SearchInquiryHandler::class, 'api.search.inquiry');
}

这是我的SearchInquiryHandler.php

class SearchInquiryHandler implements RequestHandlerInterface {
    protected $template = null;
    private $searchInquiry;
    private $containerName;
    
    public function __construct(TemplateRendererInterface $template, SearchInquiryresultForm $form, SearchInquiry $searchInquiry, $containerName) {

        $this->template = $template;
        $this->searchInquiry= $searchInquiry;
    }

    public function handle(ServerRequestInterface $request) : ResponseInterface
    {
        $result = $this->searchInquiry->setInquiryValues();
        return new HtmlResponse($this->template->render('app::search-inquiryresult', [
        'entry' => $result,
        ]));
    }

    <!-- HOW TO LOAD THIS METHOD FROM THE ROUTE -->
    public function loadThisMethod(ServerRequestInterface $request) : ResponseInterface
    {
        return new JsonResponse(['ack' => time()]);
    }

这是我的SearchInquiryHandlerFactory.php

class SearchInquiryHandlerFactory {

    public function __invoke(ContainerInterface $container) : RequestHandlerInterface
    {
        $dependency   = $container->get(SearchInquiry::class);
        $template = $container->get(LaminasViewRenderer::class);
        $form = $container->get(SearchInquiryresultForm::class);
        return new SearchInquiryHandler($template,$form,$dependency,$container);
    }
}

这是我的ConfigProvider.php

public function getDependencies() : array
{
    return [
        'invokables' => [
             ****Some Code here****
         ],
         'factories'  => [
              Handler\SearchInquiryHandler::class => Handler\SearchInquiryHandlerFactory::class,
         ],
    ];
}
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1 回答 1

0

好的，我知道了 ！首先我没有将 $request 传递给$this->loadthismethod($request);内部handle()

Class SearchInquiryHandler其次，如果您希望多条路线指向相同 handle()

您可以指定具有唯一名称的路线

$app->post('/api/search/inquiry', App\Handler\SearchInquiryHandler::class, 'api.search.inquiry');

$app->get('/api/search/test', App\Handler\SearchInquiryHandler::class, 'api.search.test');

在里面handle()你可以检查路由 URL 并根据需要加载不同的方法

$uri = $request->getUri();
$path = $uri->getPath(); 

if($path!='/api/search/inquiry'){
    return $this->postAjax($request);
}else{
    return new HtmlResponse($this->template->render('app::search-inquiryresult', [
        'entry' => $somedata,
    ]));
}

或者，如果您只有一个 http 请求方法，例如单个类GET的POST所有方法，您可以执行以下操作

$app->get('/api/search[/{action:inquiry|test}[/{id}]]', App\Handler\SearchInquiryHandler::class, 'api.search.inquiry',['GET']);

我相信有更好的方法来处理这个

于 2020-11-17T19:53:32.123 回答