我一直在用 python 编写一个程序，模拟 100 次抛硬币并给出抛硬币的总数。问题是我还想打印正面和反面的总数。
这是我的代码：
import random
tries = 0
while tries < 100:
tries += 1
coin = random.randint(1, 2)
if coin == 1:
print('Heads')
if coin == 2:
print ('Tails')
total = tries
print(total)
我一直在绞尽脑汁寻找解决方案，但到目前为止我一无所获。除了投掷的总数之外，还有什么方法可以打印出正面和反面的数量？
import random
samples = [ random.randint(1, 2) for i in range(100) ]
heads = samples.count(1)
tails = samples.count(2)
for s in samples:
msg = 'Heads' if s==1 else 'Tails'
print msg
print "Heads count=%d, Tails count=%d" % (heads, tails)
您有一个尝试次数的变量，它允许您在最后打印它，因此只需对正面和反面的数量使用相同的方法。在循环外创建一个heads和变量，在相关块内递增，然后在最后打印结果。tailsif coin == X
import random
total_heads = 0
total_tails = 0
count = 0
while count < 100:
coin = random.randint(1, 2)
if coin == 1:
print("Heads!\n")
total_heads += 1
count += 1
elif coin == 2:
print("Tails!\n")
total_tails += 1
count += 1
print("\nOkay, you flipped heads", total_heads, "times ")
print("\nand you flipped tails", total_tails, "times ")
跟踪磁头数量：
import random
tries = 0
heads = 0
while tries < 100:
tries += 1
coin = random.randint(1, 2)
if coin == 1:
heads += 1
print('Heads')
if coin == 2:
print ('Tails')
total = tries
print('Total heads '.format(heads))
print('Total tails '.format(tries - heads))
print(total)
import random
tries = 0
heads=0
tails=0
while tries < 100:
tries += 1
coin = random.randint(1, 2)
if coin == 1:
print('Heads')
heads+=1
if coin == 2:
print ('Tails')
tails+=1
total = tries
print(total)
print tails
print heads
# Please make sure to import random.
import random
# Create a list to store the results of the for loop; number of tosses are limited by range() and the returned values are limited by random.choice().
tossed = [random.choice(["heads", "tails"]) for toss in range(100)]
# Use .count() and .format() to calculate and substitutes the values in your output string.
print("There are {} heads and {} tails.".format(tossed.count("heads"), tossed.count("tails")))
tosses = 100
heads = sum(random.randint(0, 1) for toss in range(tosses))
tails = tosses - heads
您可以使用random.getrandbits()一次生成所有 100 个随机位：
import random
N = 100
# get N random bits; convert them to binary string; pad with zeros if necessary
bits = "{1:>0{0}}".format(N, bin(random.getrandbits(N))[2:])
# print results
print('{total} {heads} {tails}'.format(
total=len(bits), heads=bits.count('0'), tails=bits.count('1')))
100 45 55
我结束了这个。
import random
flips = 0
heads = 0
tails = 0
while flips < 100:
flips += 1
coin = random.randint(1, 2)
if coin == 1:
print("Heads")
heads += 1
else:
print("Tails")
tails += 1
total = flips
print(total, "total flips.")
print("With a total of,", heads, "heads and", tails, "tails.")
这是我的代码。希望它会有所帮助。
import random
coin = random.randint (1, 2)
tries = 0
heads = 0
tails = 0
while tries != 100:
if coin == 1:
print ("Heads ")
heads += 1
tries += 1
coin = random.randint(1, 2)
elif coin == 2:
print ("Tails ")
tails += 1
tries += 1
coin = random.randint(1, 2)
else:
print ("WTF")
print ("Heads = ", heads)
print ("Tails = ", tails)
import random
print("coin flip begins for 100 times")
tails = 0
heads = 0
count = 0
while count < 100: #to flip not more than 100 times
count += 1
result = random.randint(1,2) #result can only be 1 or 2.
if result == 1: # result 1 is for heads
print("heads")
elif result == 2: # result 2 is for tails
print("tails")
if result == 1:
heads +=1 #this is the heads counter.
if result == 2:
tails +=1 #this is the tails counter.
# with all 3 being the count, heads and tails counters,
# i can instruct the coin flip not to exceed 100 times, of the 100 flips
# with heads and tails counter,
# I now have data to display how of the flips are heads or tails out of 100.
print("completed 100 flips") #just to say 100 flips done.
print("total tails is", tails) #displayed from if result == 2..... tails +=1
print("total heads is", heads)