python - 我的 guizero 代码的背景颜色没有更新

Question

我的 guizero 代码的背景颜色没有更新。它以灰色开始并保持灰色（颜色选项为蓝色、橙色、红色），但打印语句给出了适当的值。温度值在 GUI 中正常更新。bg_color 分配的哪一部分不正确？

from guizero import *
import random   

def read_sensor():
    return random.randrange(3200, 5310, 10) / 100

def read_cpu_temp():
    tFile = open('/sys/class/thermal/thermal_zone0/temp')
    temp = float(tFile.read())
    return temp/1000

def update_label():
    text.value = read_cpu_temp()
    text.value = bg_color()
    # recursive call
    text.after(1000, update_label)  
def bg_color():
    print (read_cpu_temp())
    if read_cpu_temp() < 45.000:
        bg_color = "#00BFFF"
        print ("blue")
    elif 45.000 < read_cpu_temp() < 60.000:
        bg_color = "#FF8C00"
        print ("orange")
    else:
        bg_color = "#FF0000"
        print ("red")  

if __name__ == '__main__':
    app = App(title='Core Temp', height=30, width=100, layout='grid', bg = bg_color())
    title = Text(app, "Temp:", grid=[0, 0], color="white")
    text = Text(app, "xx", grid=[1, 0], color="white")
    text.after(1000, update_label)
    app.display()

Answer 1

我认为这是正确的方法，我得到了正确的

from guizero import *
import random   

def read_sensor():
    return random.randrange(3200, 5310, 10) / 100

def read_cpu_temp():
    tFile = open('/sys/class/thermal/thermal_zone0/temp')
    temp = float(tFile.read())
    return temp / 1000

def update_label():
    text.value = read_cpu_temp()
    text.value = bg_color()
    # recursive call
    text.after(1000, update_label)  
def bg_color():
    print(read_cpu_temp())
    if read_cpu_temp() < 45.000:
        app.bg = "#00BFFF"
        print ("blue")
    elif 45.000 < read_cpu_temp() < 60.000:
        app.bg = "#FF8C00"
        print("orange")
    else:
        app.bg = "#FF0000"
        print("red")  

if __name__ == '__main__':
    app = App(title='Core Temp', height=30, width=100, layout='grid')
    title = Text(app, "Temp:", grid=[0, 0], color="white")
    text = Text(app, "xx", grid=[1, 0], color="white")
    text.after(1000, update_label)
    app.display()