下面是示例代码:
from PyQt5 import QtCore, QtGui, QtWidgets
class Ui_MainWindow(object):
def setupUi(self, MainWindow):
MainWindow.setObjectName("MainWindow")
MainWindow.resize(394, 356)
self.centralwidget = QtWidgets.QWidget(MainWindow)
self.centralwidget.setObjectName("centralwidget")
self.listWidget = QtWidgets.QListWidget(self.centralwidget)
self.listWidget.setGeometry(QtCore.QRect(60, 30, 241, 192))
self.listWidget.setObjectName("listWidget")
self.pushButton = QtWidgets.QPushButton(self.centralwidget)
self.pushButton.setGeometry(QtCore.QRect(130, 250, 75, 23))
self.pushButton.setObjectName("pushButton")
MainWindow.setCentralWidget(self.centralwidget)
self.menubar = QtWidgets.QMenuBar(MainWindow)
self.menubar.setGeometry(QtCore.QRect(0, 0, 394, 21))
self.menubar.setObjectName("menubar")
MainWindow.setMenuBar(self.menubar)
self.statusbar = QtWidgets.QStatusBar(MainWindow)
self.statusbar.setObjectName("statusbar")
MainWindow.setStatusBar(self.statusbar)
self.retranslateUi(MainWindow)
QtCore.QMetaObject.connectSlotsByName(MainWindow)
players = ["Player 1","Player 2","Player 3","Player 4"]
for i in players:
item = QtWidgets.QListWidgetItem(i)
item.setFlags(item.flags() | QtCore.Qt.ItemIsUserCheckable)
item.setCheckState(QtCore.Qt.Unchecked)
self.listWidget.addItem(item)
self.selected_list = ["Player 1", "Player 4"]
self.pushButton.clicked.connect(self.find_the_list)
def retranslateUi(self, MainWindow):
_translate = QtCore.QCoreApplication.translate
MainWindow.setWindowTitle(_translate("MainWindow", "MainWindow"))
self.pushButton.setText(_translate("MainWindow", "PushButton"))
def find_the_list(self):
print("OKAY")
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
MainWindow = QtWidgets.QMainWindow()
ui = Ui_MainWindow()
ui.setupUi(MainWindow)
MainWindow.show()
sys.exit(app.exec_())
该players = ["Player 1","Player 2","Player 3","Player 4"]
列表已作为 UserCheckable 添加到 QListWidgetItem。第二个列表self.selected_list = ["Player 1", "Player 4"]
有两个项目,第二个列表是可变的。如果第二个列表有匹配的项目,现在我想检查 QlistWidgetitems 的框。