<asp:GridView ID="GridView1" runat="server">
<Columns>
<asp:TemplateField HeaderText="FileName">
<ItemTemplate>
<asp:HyperLink ID="HyperLink1" runat="server" NavigateUrl="" Text=""></asp:HyperLink>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
aspx.cs 文件
SqlCommand comm = new SqlCommand(Select
FileUpload.FileName AS FileName,
FileUpload.FilePath AS PATH,
SubjectMaster.SubjectName AS Subject,
MemberPersonalInformation.FirstName As SharedBy
from FileUpload",conn)
我需要在 Grid 中打印FileName(As Hyperlink)
, SharedBy
,Subject
我该怎么做?
我需要做这样的事情......但下面的方法不起作用
conn.Open();
SqlDataReader rdr = comm.ExecuteReader();
int i = 0;
while (rdr.Read())
{
string fip = rdr["PATH"].ToString();
HyperLink h1 = (HyperLink)GridView1.Rows[i].Cells[0].FindControl("Hyperlink1");
h1.Text = rdr["FileName"].ToString();
h1.NavigateUrl = "download.aspx?filepath=" + fip;
GridView1.Rows[i].Cells[1].Text = rdr["SharedBy"].ToString();
GridView1.Rows[i].Cells[2].Text = rdr["Subject"].ToString();
GridView1.Rows[i].Cells[3].Text = rdr["PATH"].ToString();
//GridView1.Rows[i].Rows.Add(di);
i++;
}