14

我正在尝试获取 Android 联系人收藏夹列表中的所有联系人。目前，我可以获取所有组 ID，包括最喜欢的组 ID。但似乎没有将群组 ID 作为收藏群组 ID 的联系人。

我正在尝试获取每个组中的所有组 ID 和联系人。打印两个列表后发现收藏夹的group id不在联系人列表中

ArrayList<String> favGroupId=new ArrayList<String>();
        final String[] GROUP_PROJECTION = new String[] {
                ContactsContract.Groups._ID, ContactsContract.Groups.TITLE };
        Cursor  cursor = getContentResolver().query(
        ContactsContract.Groups.CONTENT_URI, GROUP_PROJECTION, null,
                null, ContactsContract.Groups.TITLE);

        while (cursor.moveToNext()) {
            String id = cursor.getString(cursor
                    .getColumnIndex(ContactsContract.Groups._ID));
            Log.v("Test",id);

            String gTitle = (cursor.getString(cursor
                    .getColumnIndex(ContactsContract.Groups.TITLE)));

            Log.v("Test",gTitle);
            if (gTitle.contains("Favorite_")) {
                gTitle = "Favorites";
                favGroupId.add(id);
            }
        }
        cursor.close();
4

4 回答 4

24

您可以使用ContactsContract.Contact类中的STARRED字段。如果您将查询更改为：

Cursor cursor = this.managedQuery(
    ContactsContract.Contacts.CONTENT_URI, projection, "starred=?",
    new String[] {"1"}, null);

这应该返回显示在 Android 上默认联系人应用程序的“收藏夹”选项卡中的所有联系人的列表。

于 2011-06-15T03:44:27.737 回答
5

完整的答案，包括使用 Intent 打开联系人的 intentUriString：

Map getFavoriteContacts(){

    Map contactMap = new HashMap();

    Uri queryUri = ContactsContract.Contacts.CONTENT_URI;

    String[] projection = new String[] {
            ContactsContract.Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME,
            ContactsContract.Contacts.STARRED};

    String selection =ContactsContract.Contacts.STARRED + "='1'";

    Cursor cursor = managedQuery(queryUri, projection, selection, null, null);

    while (cursor.moveToNext()) {
        String contactID = cursor.getString(cursor
                .getColumnIndex(ContactsContract.Contacts._ID));

        Intent intent = new Intent(Intent.ACTION_VIEW);
        Uri uri = Uri.withAppendedPath(
            ContactsContract.Contacts.CONTENT_URI, String.valueOf(contactID));
        intent.setData(uri);
        String intentUriString = intent.toUri(0);

        String title = (cursor.getString(
            cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)));

        contactMap.put(title,intentUriString);
    }

    cursor.close();
    return contactMap;
}
于 2013-09-19T10:47:53.317 回答
2

与 Kotlin 一起使用：

import android.content.Context
import android.provider.ContactsContract
import android.content.Intent
import android.net.Uri


fun getFavoriteContacts(context: Context): Map<*, *> {

    lateinit var contactMap : HashMap<String, String>

    val queryUri = ContactsContract.Contacts.CONTENT_URI.buildUpon()
            .appendQueryParameter(ContactsContract.Contacts.EXTRA_ADDRESS_BOOK_INDEX, "true")
            .build()

    val projection = arrayOf(
            ContactsContract.Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME,
            ContactsContract.Contacts.STARRED
    )

    val selection = ContactsContract.Contacts.STARRED + "='1'"

    val cursor = context.getContentResolver().query(queryUri,
            projection, selection, null, null)

    while (cursor.moveToNext()) {
        val contactID = cursor.getString(cursor
                .getColumnIndex(ContactsContract.Contacts._ID))

        val intent = Intent(Intent.ACTION_VIEW)
        val uri = Uri.withAppendedPath(
                ContactsContract.Contacts.CONTENT_URI, contactID.toString())
        intent.data = uri
        val intentUriString = intent.toUri(0)

        val title = cursor.getString(
                cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME))

        contactMap[title] = intentUriString
    }

    cursor.close()
    return contactMap
}
于 2018-04-02T04:05:26.640 回答
0

这是在Java中获取收藏夹联系方式的完整方法

ContentResolver contentResolver = context.getContentResolver();

    if (contentResolver == null)
        return;

    String[] fieldListProjection = {
            ContactsContract.CommonDataKinds.Phone.CONTACT_ID,
            ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME_PRIMARY,
            ContactsContract.CommonDataKinds.Phone.NUMBER,
            ContactsContract.CommonDataKinds.Phone.NORMALIZED_NUMBER,
            ContactsContract.Contacts.HAS_PHONE_NUMBER,
            ContactsContract.Contacts.PHOTO_URI
            ,ContactsContract.Contacts.STARRED
    };
    String sort = ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME_PRIMARY + " ASC";
    Cursor phones = contentResolver
            .query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI
                    , fieldListProjection, null, null, sort);
    HashSet<String> normalizedNumbersAlreadyFound = new HashSet<>();

    if (phones != null && phones.getCount() > 0) {
        while (phones.moveToNext()) {
            String normalizedNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));

            if (Integer.parseInt(phones.getString(phones.getColumnIndex(
                    ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
                if (normalizedNumbersAlreadyFound.add(normalizedNumber)) {

                    int id = phones.getInt(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID));
                    String name = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                    String phoneNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));

                    int fav = phones.getInt(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.STARRED));
                    boolean isFav;
                    isFav= fav == 1;

                    String uri = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_URI));
                    if(uri!=null){
                        contactList.add(new FavContact(id,isFav,name,phoneNumber,uri));
                    }
                    else{
                        contactList.add(new FavContact(id,isFav,name,phoneNumber));
                    }

                }
            }
        }
        phones.close();
    }
于 2021-09-18T11:50:07.830 回答