我明白出了什么问题。该boost::math::factorial
函数根据定义unsigned
采用整数:
template <class T>
inline T factorial(unsigned i)
{
return factorial<T>(i, policies::policy<>());
}
这意味着如果你用双精度调用它,它将被隐式转换为无符号。那不是你想要的。此外,factorial
最终在tgamma
内部使用,所以你得到这个:
#include <boost/math/special_functions/factorials.hpp>
#include <iostream>
void foo(long double x) {
using namespace boost::math;
try {
auto f = factorial<long double>(x);
std::cout << "factorial of " << static_cast<unsigned>(x) << " = " << f << "\n";
} catch(std::exception const& e) {
std::cout << "error at " << static_cast<unsigned>(x) << ": " << std::quoted(e.what()) << "\n";
}
}
int main() {
std::cout << std::unitbuf;
foo(-2);
}
最终会这样做:
#0 boost::math::tgamma<long double, boost::math::policies::policy<boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy> > (a=4294967295, z=...)
at /home/sehe/custom/boost_1_73_0/boost/math/special_functions/gamma.hpp:1994
No locals.
#1 0x0000555555558eb3 in boost::math::factorial<long double, boost::math::policies::policy<boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy, boost::math::policies::default_policy> > (i=4294967294, pol=...)
at /home/sehe/custom/boost_1_73_0/boost/math/special_functions/factorials.hpp:44
result = -0.667762310955655363645
#2 0x0000555555558674 in boost::math::factorial<long double> (i=4294967294)
at /home/sehe/custom/boost_1_73_0/boost/math/special_functions/factorials.hpp:53
No locals.
#3 0x0000555555557792 in foo (x=-2) at /home/sehe/Projects/stackoverflow/test.cpp:7
f = <invalid float value>
#4 0x000055555555791f in main () at /home/sehe/Projects/stackoverflow/test.cpp:16
No locals.
所以它试图给你boost::math::factorial<long double> (i=4294967294)
使固定
不要factorials
用于非负整数以外的值。
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#include <boost/math/special_functions/factorials.hpp>
#include <iostream>
void foo(long double x) {
using namespace boost::math;
try {
auto tg = tgamma<long double>(x);
std::cout << "tgamma of " << x << " = " << tg << "\n" << std::endl;
} catch(std::exception const& e) {
std::cout << "error at " << x << ": " << std::quoted(e.what()) << std::endl;
}
}
int main() {
for (auto x : { 1., 2., 3., 4., 5., -.2, -2., -.5, -1.5 })
foo(x);
}
印刷:
tgamma of 1 = 1
tgamma of 2 = 1
tgamma of 3 = 2
tgamma of 4 = 6
tgamma of 5 = 24
tgamma of -0.2 = -5.82115
error at -2: "Error in function boost::math::tgamma<long double>(long double): Evaluation of tgamma at a negative integer -2."
tgamma of -0.5 = -3.54491
tgamma of -1.5 = 2.36327
可以理解的是,它在 处溢出-2
,但这是正确的。