1

当我发送获取请求以检索最新地址时，它可以正常工作，但是当我尝试发送发布请求以生成新地址时，我收到此错误身份验证错误无效签名

我确定一切都是正确的，因为我遵循了他们的文档，但我想他们需要更新它

$apiKey = "xx";
$apiSecret = "xxx"; 

$accountId = "accountx";      

$body = '';
$timestamp = time();
$message = $timestamp . 'GET' . '/v2/user' . $body;
$signature = hash_hmac('SHA256', $message, $apiSecret);
$version = '2020-06-23';

$headers = array(
    'CB-ACCESS-SIGN: ' . $signature,
    'CB-ACCESS-TIMESTAMP: ' . $timestamp,
    'CB-ACCESS-KEY: ' . $apiKey,
    'CB-VERSION: ' . $version
); 

$api_url = 'https://api.coinbase.com/v2/user';

$ch = curl_init(); 
curl_setopt($ch, CURLOPT_URL, $api_url);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, 1);
    
$data = curl_exec($ch);

curl_close($ch);

$ctx = stream_context_create(["http"=>["user_agent"=>"Mozilla/5.0 (Macintosh; Intel Mac OS X 10.14; rv:63.0) Gecko/20100101 Firefox/63.0"]]);

$response_btc = file_get_contents('https://api.coinbase.com/v2/prices/BTC-USD/spot', true, $ctx);

$object_btc = json_decode($response_btc, true);

$usdprice = $object_btc["data"]["amount"];
$btcamount = number_format($amount/$usdprice, 8, '.', '');                    



$body1 = '';
$timestamp1 = time();
$message1 = $timestamp1 . 'POST' . '/v2/accounts/accountx/addresses' . $body1;
$signature1 = hash_hmac('SHA256', $message1, $apiSecret);
$version1 = '2020-06-23';

$headers1 = array(
    'CB-ACCESS-SIGN: ' . $signature1,
    'CB-ACCESS-TIMESTAMP: ' . $timestamp1,
    'CB-ACCESS-KEY: ' . $apiKey,
    'CB-VERSION: ' . $version1,
    'Content-Type: appliaction/json'
); 

$api_url = "https://api.coinbase.com/v2/accounts/accountx/addresses";

$ch = curl_init(); 
curl_setopt($ch, CURLOPT_URL, $api_url);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "{\"name\": \"New receive address\"}");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");                         


  
$data1 = curl_exec($ch);

if(curl_errno($ch))
{
    echo "Errore: " . curl_error($ch);
}
else
{
    echo $data1;
}

curl_close($ch);
4

1 回答 1

0

我遇到了同样的错误，我使用以下方法解决了它：

json_encode($body);
于 2020-08-10T08:02:16.667 回答