ios - 我如何通过其记录名称查询 CloudKit 以获取特定记录？

Question

我如何通过其记录名称查询 CloudKit 以获取特定记录？

以下代码给了我一个错误。

let recordName = "BBBA9068-D01A-9D55-3D6B-4460A7B36D57"
let predicate = NSPredicate(format: "recordID=%@", recordName)
let query = CKQuery(recordType: "Route", predicate: predicate)

privateDatabase.perform(query, inZoneWith: nil) {

    (records: [CKRecord]?, error: Error?) in

    if error != nil {

        print(error!.localizedDescription)

    } else {

        if let records = records {

            print(records.first as Any)

        }

    }

}

调试窗口显示：

字段“___recordID”的值类型为 REFERENCE，无法使用筛选值类型 STRING 进行查询

Answer 1

我更改了代码的前两行并让它工作。

let recordID: CKRecord.ID = CKRecord.ID(recordName: "BBBA9068-D01A-9D55-3D6B-4460A7B36D57")
let predicate = NSPredicate(format: "recordID=%@", recordID)
let query = CKQuery(recordType: "Route", predicate: predicate)

privateDatabase.perform(query, inZoneWith: nil) {

    (records: [CKRecord]?, error: Error?) in

    if error != nil {

        print(error!.localizedDescription)

    } else {

        if let records = records {

            print(records.first as Any)

        }

    }

}