我正在关注本教程(https://www.youtube.com/watch?v=QMR6N6Vs_x0&feature=emb_err_woyt)并将代码用于 Apple Watch 应用程序。所以一切正常。
奇怪的是,并非我输入的所有城市都被接受。它给出了错误(参见代码)“用户输入不正确!”。但是,当我复制并粘贴生成的 url 并且由于代码不正确时,它将在浏览器中工作。它将接受该输入。但我的应用程序不会。
我已经搜索过,但找不到类似的东西。我认为这是一件很小的事情。
import Foundation
final class NetService: ObservableObject {
@Published var weather: WeatherData?
@Published var city = ""
let baseURL = URL(string: "https://api.openweathermap.org/data/2.5/weather")!
var query = ["q": "", "appid": "", "units": "metric"]
func loadWeatherInfo(by city: String) {
guard baseURL.withQueries(query) != nil, city != "" else { print("URL isn't correct!"); return}
query["appid"] = "HERE I PUT MY OWN API-KEY"
query["q"] = city
URLSession.shared.dataTask(with: baseURL.withQueries(query)!) { data, _, error in
print(self.baseURL.withQueries(self.query)!)
guard let data = data else { print(#line, #function, "\(error!.localizedDescription)"); return }
if let weatherInfo = try? JSONDecoder().decode(WeatherData.self, from: data) {
DispatchQueue.main.async { [weak self] in
self?.weather = weatherInfo
}
} else {
print(#line, #function, "incorrect user input!"); return
}
}.resume()
}
}
所以我的问题是,为什么我的代码不能接受所有城市。我收到有关“Zeist”、“Woerden”、“Gent”等的错误。(https://api.openweathermap.org/data/2.5/weather?q=Zeist&appid=HERE I PUT MY OWN API-KEY&units=metric)
如果我从控制台复制“构建 url” ,当我将其粘贴到 Safari 中时,我会得到一个返回。所以这座城市得到了认可。
{"coord":{"lon":5.23,"lat":52.09},"weather":[{"id":800,"main":"Clear","description":"晴空","icon ":"01d"}],"base":"stations","main":{"temp":11.84,"feels_like":10.18,"temp_min":11.11,"temp_max":12.78,"pressure":1020 “湿度”:58},“风”:{“速度”:0.45,“度”:264,“阵风”:2.68},“云”:{“所有”:7},“dt”:1589534449, "sys":{"type":3,"id":2005313,"country":"NL","sunrise":1589514260,"sunset":1589570804},"timezone":7200,"id":2743977, “名称”:“Zeist”,“鳕鱼”:200}
所以url是正确构建的。
感谢阅读,希望有解决办法。