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我正在努力处理一个应该返回 anf64或 an的函数Error。我尝试了很多组合,但没有成功。

fn_rayon_parallel(&self) -> Result<f64, Box<dyn Error + Send + Sync>>  {

    let all_payoffs = (0..10000).into_par_iter().map( 
        |_| {   //things could go very wrong here        
                match self.get_one_payoff() {
                    Ok(payoff) => {Ok(payoff)},
                    Err(e) => Err(e)
                }
            }
    ).collect::<Result<Vec<_>, _>>();

    //this is the part I am struggling with, does not compile
    //I need to return either f64 or Error

    match all_payoffs {
        Ok(_v) => Ok(2.34 * (1.0/10000.0) * (all_payoffs.iter().sum::<f64>())),
        Err(e) => Err(From::from("There was an error in calculating Discounted Payoffs."))
    }


}

错误:

error[E0277]: the trait bound `f64: std::iter::Sum<&std::vec::Vec<f64>>` is not satisfied
  --> src/main.rs:81:69
   |
81 |             Ok(_v) => Ok(2.34 * (1.0/10000.0) * (all_payoffs.iter().sum::<f64>())),
   |                                                                     ^^^ the trait `std::iter::Sum<&std::vec::Vec<f64>>` is not implemented for `f64`
   |
   = help: the following implementations were found:
             <f64 as std::iter::Sum<&'a f64>>
             <f64 as std::iter::Sum>

操场

4

1 回答 1

3

您的主要问题在这里(简化了一点):

match all_payoffs {
    Ok(_v) => Ok(1.0 * (all_payoffs.iter().sum::<f64>())),
    Err(e) => { /*...*/ }
}

请注意,您的all_payoffs变量是Result<Vec<f64>, Box<dyn Error + Send>>. 因此,当您执行此操作时,.iter()您认为您获得了向量值的迭代器,类型为&f64,但您却获得了!!的 ok 值的迭代器。Result

这在很多情况下都很方便,例如,您可以使用if但 return ifIterator::flatten()对所有值求和:Ok()0.0Err()

let x = all_payoffs.iter().flatten().sum::<f64>();

但是这里编译器认为您正在尝试对向量求和并且无法完成,因此您会收到一条错误消息:

特征界限f64: std::iter::Sum<&std::vec::Vec<f64>>不满足

这基本上意味着:你不能总结一堆&Vec<f64>并得到f64一个结果。

解决方案就在眼前,使用它_v

Ok(v) => Ok(1.0 * v.iter().sum::<f64>()),

现在它起作用了!

于 2020-05-14T17:52:35.643 回答