26

我想使用 OpenCV 来处理我的桌面，就好像它是一个视频流一样。
我熟悉 OpenCV。
我不熟悉 Windows API。我意识到还有其他方法可以捕获屏幕，但就我的问题而言，我需要使用 OpenCV 来完成。

这是我的（超级天真）代码：

HWND hDesktopWnd;
HDC hDesktopDC;
hDesktopWnd=GetDesktopWindow();
hDesktopDC=GetDC(hDesktopWnd);

// get the height and width of the screen
int height = GetSystemMetrics(SM_CYVIRTUALSCREEN);
int width = GetSystemMetrics(SM_CXVIRTUALSCREEN);

// create a bitmap
HBITMAP hbDesktop = CreateCompatibleBitmap( hDesktopDC, width, height);

Mat src(height,width,CV_8UC4);
src.data = (uchar*)hbDesktop;

imshow("output",src);  //fails :(

StackOverflow 上也有类似的问题，但它们要么是针对旧式 OpenCV，要么是针对 Android 操作系统。
我在 Windows 7 64x
Opencv 2.4.3

感谢任何可以回答这个问题的人。

4

2 回答 2

45

经过多次试验和错误，我设法编写了一个函数来做到这一点。这是给其他可能想要的人的：

#include "stdafx.h"
#include "opencv2/core/core.hpp"
#include "opencv2/imgproc/imgproc.hpp"
#include <opencv2/highgui/highgui.hpp>
#include <Windows.h>
#include <iostream>
#include <string>
using namespace std;
using namespace cv;

Mat hwnd2mat(HWND hwnd){

    HDC hwindowDC,hwindowCompatibleDC;

    int height,width,srcheight,srcwidth;
    HBITMAP hbwindow;
    Mat src;
    BITMAPINFOHEADER  bi;

    hwindowDC=GetDC(hwnd);
    hwindowCompatibleDC=CreateCompatibleDC(hwindowDC);
    SetStretchBltMode(hwindowCompatibleDC,COLORONCOLOR);  

    RECT windowsize;    // get the height and width of the screen
    GetClientRect(hwnd, &windowsize);

    srcheight = windowsize.bottom;
    srcwidth = windowsize.right;
    height = windowsize.bottom/2;  //change this to whatever size you want to resize to
    width = windowsize.right/2;

    src.create(height,width,CV_8UC4);

    // create a bitmap
    hbwindow = CreateCompatibleBitmap( hwindowDC, width, height);
    bi.biSize = sizeof(BITMAPINFOHEADER);    //http://msdn.microsoft.com/en-us/library/windows/window/dd183402%28v=vs.85%29.aspx
    bi.biWidth = width;    
    bi.biHeight = -height;  //this is the line that makes it draw upside down or not
    bi.biPlanes = 1;    
    bi.biBitCount = 32;    
    bi.biCompression = BI_RGB;    
    bi.biSizeImage = 0;  
    bi.biXPelsPerMeter = 0;    
    bi.biYPelsPerMeter = 0;    
    bi.biClrUsed = 0;    
    bi.biClrImportant = 0;

    // use the previously created device context with the bitmap
    SelectObject(hwindowCompatibleDC, hbwindow);
    // copy from the window device context to the bitmap device context
    StretchBlt( hwindowCompatibleDC, 0,0, width, height, hwindowDC, 0, 0,srcwidth,srcheight, SRCCOPY); //change SRCCOPY to NOTSRCCOPY for wacky colors !
    GetDIBits(hwindowCompatibleDC,hbwindow,0,height,src.data,(BITMAPINFO *)&bi,DIB_RGB_COLORS);  //copy from hwindowCompatibleDC to hbwindow

    // avoid memory leak
    DeleteObject (hbwindow); DeleteDC(hwindowCompatibleDC); ReleaseDC(hwnd, hwindowDC);

    return src;
}
于 2013-01-05T01:06:56.323 回答
12

一个更好的方法是只为像素分配一次内存。所以这里唯一的副本是BitBlt制作的

在此处输入图像描述

int main()

{

    int x_size = 800, y_size = 600; // <-- Your res for the image





    HBITMAP hBitmap; // <-- The image represented by hBitmap

    Mat matBitmap; // <-- The image represented by mat





    // Initialize DCs

    HDC hdcSys = GetDC(NULL); // Get DC of the target capture..
    HDC hdcMem = CreateCompatibleDC(hdcSys); // Create compatible DC 






    void *ptrBitmapPixels; // <-- Pointer variable that will contain the potinter for the pixels









    // Create hBitmap with Pointer to the pixels of the Bitmap
    BITMAPINFO bi; HDC hdc;
    ZeroMemory(&bi, sizeof(BITMAPINFO));
    bi.bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
    bi.bmiHeader.biWidth = x_size;
    bi.bmiHeader.biHeight = -y_size;  //negative so (0,0) is at top left

    bi.bmiHeader.biPlanes = 1;

    bi.bmiHeader.biBitCount = 32;
    hdc = GetDC(NULL);
    hBitmap = CreateDIBSection(hdc, &bi, DIB_RGB_COLORS, &ptrBitmapPixels, NULL, 0);
    // ^^ The output: hBitmap & ptrBitmapPixels


    // Set hBitmap in the hdcMem 
    SelectObject(hdcMem, hBitmap);



    // Set matBitmap to point to the pixels of the hBitmap
    matBitmap = Mat(y_size, x_size, CV_8UC4, ptrBitmapPixels, 0);
    //                ^^ note: first it is y, then it is x. very confusing

    // * SETUP DONE *




    // Now update the pixels using BitBlt
    BitBlt(hdcMem, 0, 0, x_size, y_size, hdcSys, 0, 0, SRCCOPY);


    // Just to do some image processing on the pixels.. (Dont have to to this)
    Mat matRef = matBitmap(Range(100, 200), Range(100, 200));
    //                              y1    y2            x1     x2
    bitwise_not(matRef, matRef); // Invert the colors in this x1,x2,y1,y2




    // Display the results through Mat
    imshow("Title", matBitmap);

    // Wait until some key is pressed

    waitKey(0);


    return 0;


}

请注意，这里没有进行错误处理以使其易于理解，但您必须在代码中进行错误处理！

希望这可以帮助

于 2016-04-01T08:27:13.667 回答