操作系统:Ubuntu 16.04
我尝试在 ssh2_exec 中使用变量,但收到以下消息:
PID TTY TIME CMD 12585 pts/0 05:27:05 samp03svr bash: line 1: -o: command not found
我的代码:
include('Net/SSH2.php');
$cmd = "sudo ps -p {$user->sshConnect()} -o %cpu";
$ssh = new Net_SSH2('IP');
if (!$ssh->login('username', 'password')) {
exit('Login Failed');
}
echo $ssh->exec($cmd);
sshConnect 功能:
public function sshConnect(){
$connection = ssh2_connect('IP', 22);
ssh2_auth_password($connection, 'username', 'password');
$stream = ssh2_exec($connection, 'lsof -t -i :6000');
stream_set_blocking($stream, true);
$out = ssh2_fetch_stream($stream, SSH2_STREAM_STDIO);
return stream_get_contents($out);
}
但是,如果我用我当前的 PID 替换 {$user->sshConnect()},它就可以正常工作。还有 $user->sshConnect(),当我回显它时返回有效的 PID。
谢谢。