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我有这个代码:

datatype 'a tree = Leaf of 'a | Node of 'a * 'a tree * 'a tree | Nil;
val rec tree_sum = fn(f,e,Nil) => e 
                   | (f,e,Leaf(n)) => n 
                   | (f,e,Node(node,right,left)) =>     
                               f(node,tree_sum(f,e,right),tree_sum(f,e,left));

val binnum = Node(5,Leaf(4),Node(2,Leaf(1),Node(8,Nil,Nil)));
tree_sum((fn(a,b,c)=> a+b+c),0,binnum);
val it = 20 : int

treesum当我有另一种数据类型时,如何执行相同的过程:

datatype 'a stree = Leaf of 'a | Brnch of 'a stree list;

treesum(fn(a, b) => a + b, 0, Brnch([Leaf 2, Brnch([Leaf 5, Leaf 3, Leaf 8])]));
val it = 18 : int

我认为我必须使用地图......我试试这个,但有 3 个错误

val rec treesum = 
         fn (f,e,nil) => e 
            | (f,e,Leaf(n)) => n 
            | (f,e,Brnch(h::lst)) => 
                   f(treesum(f,e,h),treesum(f,e,lst));
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1 回答 1

1

有两个地方你做错了。首先,nil不是astree而是Brnch nila stree。其次,lst不是一棵树,而是Brnch lst一棵stree。您可以按如下方式更正您的功能(为了便于阅读,我对案例进行了重新排序):

val rec treesum = 
         fn (f,e,Leaf(n)) => n 
            | (f,e,Brnch nil) => e 
            | (f,e,Brnch(h::lst)) => 
                   f(treesum(f,e,h),treesum(f,e,Brnch lst));

还有一件事,您应该按照数据类型的结构编写函数。List所以使用函数的以下版本更好:

val rec treesum = 
         fn (f,e,Leaf(n)) => n 
            | (f,e,Brnch ls) => 
                   List.foldl (fn (l, acc) => f(treesum(f,e,l), acc)) e ls;
于 2011-05-30T07:24:08.993 回答