0
If AnswerOrder(0) = 1 Then
ActivePresentation.Slides(3).Shapes("a1").Left = 303
ActivePresentation.Slides(3).Shapes("a1").Top = 218
ElseIf AnswerOrder(0) = 2 Then
ActivePresentation.Slides(3).Shapes("a1").Left = 303
ActivePresentation.Slides(3).Shapes("a1").Top = 290
ElseIf AnswerOrder(0) = 3 Then
ActivePresentation.Slides(3).Shapes("a1").Left = 303
ActivePresentation.Slides(3).Shapes("a1").Top = 361
ElseIf AnswerOrder(0) = 4 Then
ActivePresentation.Slides(3).Shapes("a1").Left = 303
ActivePresentation.Slides(3).Shapes("a1").Top = 432
End If

If AnswerOrder(1) = 1 Then
ActivePresentation.Slides(3).Shapes("a2").Left = 303
ActivePresentation.Slides(3).Shapes("a2").Top = 218
ElseIf AnswerOrder(1) = 2 Then
ActivePresentation.Slides(3).Shapes("a2").Left = 303
ActivePresentation.Slides(3).Shapes("a2").Top = 290
ElseIf AnswerOrder(1) = 3 Then
ActivePresentation.Slides(3).Shapes("a2").Left = 303
ActivePresentation.Slides(3).Shapes("a2").Top = 361
ElseIf AnswerOrder(1) = 4 Then
ActivePresentation.Slides(3).Shapes("a2").Left = 303
ActivePresentation.Slides(3).Shapes("a2").Top = 432
End If

If AnswerOrder(2) = 1 Then
ActivePresentation.Slides(3).Shapes("a3").Left = 303
ActivePresentation.Slides(3).Shapes("a3").Top = 218
ElseIf AnswerOrder(2) = 2 Then
ActivePresentation.Slides(3).Shapes("a3").Left = 303
ActivePresentation.Slides(3).Shapes("a3").Top = 290
ElseIf AnswerOrder(2) = 3 Then
ActivePresentation.Slides(3).Shapes("a3").Left = 303
ActivePresentation.Slides(3).Shapes("a3").Top = 361
ElseIf AnswerOrder(2) = 4 Then
ActivePresentation.Slides(3).Shapes("a3").Left = 303
ActivePresentation.Slides(3).Shapes("a3").Top = 432
End If

If AnswerOrder(3) = 1 Then
ActivePresentation.Slides(3).Shapes("a4").Left = 303
ActivePresentation.Slides(3).Shapes("a4").Top = 218
ElseIf AnswerOrder(3) = 2 Then
ActivePresentation.Slides(3).Shapes("a4").Left = 303
ActivePresentation.Slides(3).Shapes("a4").Top = 290
ElseIf AnswerOrder(3) = 3 Then
ActivePresentation.Slides(3).Shapes("a4").Left = 303
ActivePresentation.Slides(3).Shapes("a4").Top = 361
ElseIf AnswerOrder(3) = 4 Then
ActivePresentation.Slides(3).Shapes("a4").Left = 303
ActivePresentation.Slides(3).Shapes("a4").Top = 432
End If

必须有更好的方法来执行这个宏,而不是写这么多行。有什么建议么?

上下文:我正在尝试随机打乱幻灯片 3 中四个形状的顺序。我创建了一个名为AnswerOrderwhich contains的数组1,2,3,4。我打乱数组,然后执行上面的代码。

4

2 回答 2

2

抱歉,我手头没有 PowerPoint,但我在 Excel 中编写了一些示例代码,希望这将有助于缩短代码一点,使其更易于维护。

这个想法是将设置形状位置的代码提取到单独的子程序中,并在主子程序中迭代 AnswerOrder 并在指定的形状上调用该子程序。

Public Sub set_shapePosition(determinant As Long, shp As Shape)
    ' can also put shp.Left = 303 here
    Select Case determinant
        Case 1
            shp.Left = 303
            shp.Top = 218
        Case 2
            shp.Left = 303
            shp.Top = 290
        Case 3
            shp.Left = 303
            shp.Top = 361
        Case 4
            shp.Left = 303
            shp.Top = 432
    End Select
    ' Also shape Top is around 71 pixels different to one and another,
    ' We can write below code for simpler implementation
    ' Getting rid of select case statement:
    ' shp.Top = 218 + 71 * (determinant - 1)
End Sub

Public Sub main()
    ' Define slide here.....
    Set slide = ActivePresentation.Slides(3)

    ' ...Define and shuffle AnswerOrder here.......
    '
    ' .............................................

    For i = LBound(AnswerOrder) To UBound(AnswerOrder)
        Call set_shapePosition(AnswerOrder(i), slide.Shapes("a" & i+1) )
    Next i
End Sub
于 2020-05-08T04:47:34.367 回答
0
For j = 0 To 3

If AnswerOrder(j) = 1 Then
ActivePresentation.Slides(3).Shapes("a" & j + 1).Top = 218
ActivePresentation.Slides(3).Shapes("a" & j + 1).Left = 303
ElseIf AnswerOrder(j) = 2 Then
ActivePresentation.Slides(3).Shapes("a" & j + 1).Top = 288
ActivePresentation.Slides(3).Shapes("a" & j + 1).Left = 303
ElseIf AnswerOrder(j) = 3 Then
ActivePresentation.Slides(3).Shapes("a" & j + 1).Top = 363
ActivePresentation.Slides(3).Shapes("a" & j + 1).Left = 303
ElseIf AnswerOrder(j) = 4 Then
ActivePresentation.Slides(3).Shapes("a" & j + 1).Top = 432
ActivePresentation.Slides(3).Shapes("a" & j + 1).Left = 303
End If

Next j

这使代码更加整洁。

于 2020-05-09T09:41:58.907 回答