我是 Lex 和 Yacc 的新手。我尝试学习语法规则和语义动作。我试图编写一个解析器,它基本上可以执行赋值、函数声明、函数调用和打印语句。问题是,在我给出输入后,我得到的输出是语法错误。所以我认为我的语法会导致这种情况,但我不确定。这是我的文件:
扫描仪.flx:
%option noyywrap
%option yylineno
%{
#include "parser.tab.h"
%}
IDENT [a-zA-Z_][a-zA-Z0-9_]*
INT -?[0-9]+
STRING "[\S\s]*?"
UNFSTRING "[\S\s]*?[^"]$
%%
"int" return tINT;
"string" return tSTRING;
"return" return tRETURN;
"print" return tPRINT;
"(" return tLPAR;
")" return tRPAR;
"," return tCOMMA;
"%" return tMOD;
"=" return tASSIGNM;
"-" return tMINUS;
"+" return tPLUS;
"/" return tDIV;
"*" return tSTAR;
";" return tSEMI;
"{" return tLBRAC;
"}" return tRBRAC;
{IDENT} return tIDENT;
{INT} return tINTVAL;
{STRING} return tSTRINGVAL;
{UNFSTRING} return tUNFSTRING;
[ \t\n]+
. { /* pass any other character to the parser */
return yytext[0];
}
%%
解析器.y:
%{
#include <stdio.h>
void yyerror (const char *s)
{
printf ("%s\n", s);
}
%}
%token tINT tSTRING tRETURN tPRINT tLPAR tRPAR tCOMMA tMOD tASSIGNM tMINUS tPLUS tDIV tSTAR tSEMI tLBRAC tRBRAC tIDENT tINTVAL tSTRINGVAL tUNFSTRING
%left '='
%left '+' '-'
%left '*' '/'
%left '(' ')'
%%
CVD19 : stmtlst
;
stmtlst : stmtlst stmt
| stmt
;
stmt : funcDecl
| varDecl
| assgnmt
| callfunc
| printstmt
;
funcDecl : type tIDENT '(' ')' '{' funcbody return '}' { printf("FUNCTION "); }
| type tIDENT '(' funcparams ')' '{' funcbody return '}' { printf("FUNCTION W/PARAMS "); }
;
funcbody : varDecl
| assgnmt
| callfunc
| printstmt
;
return : tRETURN expr ';'
;
funcparams : funcparams ',' type tIDENT
| type tIDENT
;
varDecl : type vars '=' expr ';'
;
type : tINT { printf("INT TYPE "); }
| tSTRING { printf("STRING TYPE "); }
;
assgnmt : tIDENT '=' expr ';' { printf("ASSIGNMENT"); }
;
callfunc : tIDENT '(' ')' ';' { printf("FUNCTION CALL"); }
| tIDENT '(' vars ')' ';' { printf("FUNCTION W/PARAMs CALL"); }
;
printstmt : tPRINT '(' expr ')' ';' { printf("PRINTSTMT 1"); }
| tPRINT '(' callfunc ')' ';' { printf("PRINTSTMT 2"); }
;
vars : vars ',' tIDENT
| tIDENT { printf("IDENT "); }
;
expr : value
| expr '+' expr { $$ = $1 + $3; }
| expr '-' expr { $$ = $1 - $3; }
| expr '*' expr { $$ = $1 * $3; }
| expr '/' expr { $$ = $1 / $3; }
;
value : tINTVAL { printf("INTVAL "); }
| tSTRINGVAL { printf("STRINGVAL "); }
| tUNFSTRING { printf("UNFSTRING "); }
/*| tIDENT MIGHT BE PROBLEMATIC { $$ = $1; }*/
;
%%
int main ()
{
if (yyparse()) {
// parse error
printf("ERROR\n");
return 1;
}
else {
// successful parsing
printf("OK\n");
return 0;
}
}
当我尝试在 MacOS 终端中运行我的文件时,我照常使用这些命令:
flex scanner.flx
- 没问题 -
bison -d parser.y
- 没问题 -
gcc -o program lex.yy.c parser.tab.c -ll
- 警告 -
parser.tab.c:1330:16: warning: implicit declaration of function 'yylex' is invalid in C99 [-Wimplicit-function-declaration] yychar = YYLEX; ^ parser.tab.c:686:16: note: expanded from macro 'YYLEX' # define YYLEX yylex () ^ 1 warning generated.
这是 parser.tab.c 中的第 1330 行附近:
/* First try to decide what to do without reference to look-ahead token. */ yyn = yypact[yystate]; if (yyn == YYPACT_NINF) goto yydefault; /* Not known => get a look-ahead token if don't already have one. */ /* YYCHAR is either YYEMPTY or YYEOF or a valid look-ahead symbol. */ if (yychar == YYEMPTY) { YYDPRINTF ((stderr, "Reading a token: ")); yychar = YYLEX; /* THIS IS LINE 1330 <============================================= } if (yychar <= YYEOF) { yychar = yytoken = YYEOF; YYDPRINTF ((stderr, "Now at end of input.\n")); } else { yytoken = YYTRANSLATE (yychar); YY_SYMBOL_PRINT ("Next token is", yytoken, &yylval, &yylloc); }
这是我的输入:
输入1:
int num = 123;
输出1:
INT TYPE IDENT syntax error ERROR
输入2:
print("str");
输出2:
syntax error ERROR
输入3:
int func(int i) { i = 5; return i; }
输出3:
INT TYPE IDENT syntax error ERROR