3

这是geom_tile显示一周中的小时和天数,如何显示每个小时(即 x 轴上的 00:00 到 23:00)?

library(tidyverse)
df %>% 
  ggplot(aes(hour, day, fill = value)) +
  geom_tile(colour = "ivory") 

目前它每五小时显示一次:

在此处输入图像描述

我尝试了很多不同的东西,并且更喜欢“最佳实践”的方式(即不手动生成标签),但如果需要标签,这里有一种制作它们的方法hour_labs <- 0:23 %>% { ifelse(nchar(.) == 1, paste0("0", .), .) } %>% paste0(., ":00")

可重现示例的数据


df <- structure(list(day = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 
3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 5L, 5L, 
5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 
5L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 
6L, 6L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L), .Label = c("Sunday", 
"Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"
), class = c("ordered", "factor")), hour = c(0L, 2L, 3L, 5L, 
6L, 7L, 8L, 10L, 11L, 12L, 13L, 18L, 21L, 22L, 23L, 0L, 1L, 2L, 
3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 20L, 21L, 22L, 
23L, 0L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 
20L, 21L, 22L, 23L, 0L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 
11L, 13L, 14L, 20L, 21L, 22L, 23L, 0L, 1L, 2L, 3L, 4L, 5L, 6L, 
7L, 8L, 9L, 10L, 11L, 12L, 13L, 15L, 20L, 21L, 22L, 23L, 0L, 
1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 11L, 13L, 14L, 15L, 16L, 
19L, 21L, 0L, 1L, 2L, 3L, 7L, 8L, 10L, 13L, 14L, 22L, 23L), value = c(1L, 
1L, 1L, 2L, 1L, 3L, 1L, 1L, 2L, 1L, 3L, 1L, 2L, 13L, 13L, 24L, 
39L, 21L, 17L, 25L, 22L, 27L, 28L, 19L, 6L, 2L, 2L, 1L, 2L, 2L, 
7L, 23L, 38L, 18L, 26L, 21L, 20L, 31L, 40L, 35L, 22L, 5L, 3L, 
2L, 7L, 4L, 3L, 3L, 3L, 17L, 13L, 23L, 24L, 19L, 31L, 13L, 35L, 
50L, 22L, 13L, 7L, 2L, 1L, 1L, 1L, 1L, 3L, 14L, 17L, 33L, 32L, 
32L, 25L, 29L, 27L, 38L, 26L, 11L, 8L, 4L, 5L, 5L, 3L, 1L, 1L, 
3L, 14L, 21L, 24L, 22L, 25L, 26L, 23L, 58L, 36L, 26L, 6L, 3L, 
1L, 5L, 3L, 1L, 1L, 3L, 1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 
1L, 1L)), row.names = c(NA, -116L), groups = structure(list(day = structure(1:7, .Label = c("Sunday", 
"Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"
), class = c("ordered", "factor")), .rows = structure(list(1:15, 
    16:33, 34:51, 52:69, 70:88, 89:105, 106:116), ptype = integer(0), class = c("vctrs_list_of", 
"vctrs_vctr"))), row.names = c(NA, 7L), class = c("tbl_df", "tbl", 
"data.frame"), .drop = TRUE), class = c("grouped_df", "tbl_df", 
"tbl", "data.frame"))

4

2 回答 2

2

sprintf这是用于构造标签的一种方法。

library(dplyr)
library(ggplot2)

df %>%
  mutate(lab = sprintf('%02d:00', hour)) %>%
  ggplot() + aes(lab, day, fill = value) +
  geom_tile(colour = "ivory") + 
  theme(axis.text.x = element_text(angle = 90, hjust = 1))

在此处输入图像描述


除了@Eric Watt 的建议之外,我们还可以使用complete.

df %>%
  mutate(lab = sprintf('%02d:00', hour)) %>% 
  tidyr::complete(lab = sprintf('%02d:00', 0:23)) %>%
  ggplot() + aes(lab, day, fill = value) +
  geom_tile(colour = "ivory") + 
  theme(axis.text.x = element_text(angle = 90, hjust = 1))

在此处输入图像描述

于 2020-04-22T04:08:47.783 回答
2

我建议确保您的数据类型正确表示您的数据。如果您的hour列以小时为单位表示时间,那么它应该是基于时间的结构。例如:

df$hour <- as.POSIXct(as.character(df$hour), format = "%H", tz = "UTC")

然后你可以告诉 ggplot x 轴是一个日期时间变量,使用scale_x_datetime.

ggplot(df, aes(hour, day, fill = value)) +
  geom_tile(colour = "ivory") +
  scale_x_datetime(labels = date_format("%H:%M")) + 
  theme(axis.text.x = element_text(angle = 90, hjust = 1, vjust = 0.5))

在此处输入图像描述

如果您想每小时休息一下,您可以输入休息时间:

ggplot(df, aes(hour, day, fill = value)) +
  geom_tile(colour = "ivory") +
  scale_x_datetime(breaks = as.POSIXct(as.character(0:23), format = "%H", tz = "UTC"), 
                   labels = date_format("%H:%M")) + 
  theme(axis.text.x = element_text(angle = 90, hjust = 1, vjust = 0.5))

在此处输入图像描述

您还可以使用scales具有方便格式化选项的包,例如date_breaks

library(scales)
ggplot(df, aes(hour, day, fill = value)) +
  geom_tile(colour = "ivory") +
  scale_x_datetime(breaks = date_breaks("1 hour"), 
                   labels = date_format("%H:%M")) + 
  theme(axis.text.x = element_text(angle = 90, hjust = 1, vjust = 0.5))

在此处输入图像描述

于 2020-05-07T00:22:06.993 回答