3

我有很多代理 uri(http 和 socks5),我正在使用 reqwest 通过这些代理发送一些 http 请求,如果他不工作,我想删除一个代理。

for proxy in proxies {
    let proxy = match Proxy::all(proxy_url) {
        Ok(proxy) => proxy,
        Err(e) => {
            eprintln!("creating proxy failed! {:?}", e);
            continue;
        }
    };

    let client = match Client::builder()
    .proxy(proxy)
    .build()

    let client = match client {
        Ok(client) => client,
        Err(e) => {
            eprintln!("building client failed! {:?}", e);
            continue;
        }
    }

    loop {
        match client.get(&config.endpoint).send().await {
            Ok(_) => {}
            Err(e) => {
                if e.is_proxy_error() { // this method doesn't exist
                    eprintln!("Dropping proxy...");
                    break;
                } else {
                    eprintln!("client error! {:?}", e);
                }
            }
        }
    }
}

我有很多种Reqwest::Error

reqwest::Error { kind: Request, url: "http://example.com/", source: hyper::Error(Connect, "socks connect error: Invalid response version") }
reqwest::Error { kind: Request, url: "http://example.com/", source: hyper::Error(Connect, "socks connect error: Proxy server unreachable") }
reqwest::Error { kind: Request, url: "http://example.com/", source: hyper::Error(Connect, "socks connect error: Connection refused") }
reqwest::Error { kind: Request, url: "http://example.com/", source: hyper::Error(Connect, "socks connect error: Connection reset by peer (os error 104)") }

在大多数情况下,错误消息是明确的,但我怎样才能以不同的方式处理它们?reqwest::Errorhaveinner字段是私有的,所以我无法访问他。如果我得到了的来源reqwest::Error,我只是有一个Box<syn Error>我不能像对待hyper::Error

4

1 回答 1

1

您可以将结果向下转换为Error::source()具体的错误类型,例如

use std::error::Error;

...

    Err(reqwest_error) => {
        let hyper_error: Option<&hyper::Error> = reqwest_error
            .source()
            .unwrap()
            .downcast_ref();
        ...
    }

此代码用于unwrap()Option返回的中提取错误source()。如果你不能保证错误总是有来源,你应该使用一些有条件的方式来解开来源,例如

let hyper_error: Option<&hyper::Error> = reqwest_error
    .source()
    .and_then(|e| e.downcast_ref());
于 2020-04-08T12:23:45.173 回答