11
var sql = @"SELECT
    a.id AS `Id`, 
    a.thing AS `Name`, 
    b.id AS `CategoryId`,
    b.something AS `CategoryName`  
FROM ..";

var products = connection.Query<Product, Category, Product>(sql,
    (product, category) =>
    {
        product.Category = category;
        return product;
    }, 
    splitOn: "CategoryId");

foreach(var p in products)
{
    System.Diagnostics.Debug.WriteLine("{0} (#{1}) in {2} (#{3})", p.Name, p.Id, p.Category.Name, p.Category.Id);
}

结果是:

'First (#1) in  (#0)'
'Second (#2) in  (#0)'

CategoryId 和 CategoryName 具有以下值

var products = connection.Query(sql).Select<dynamic, Product>(x => new Product
{
    Id = x.Id,
    Name = x.Name,
    Category = new Category { Id = x.CategoryId, Name = x.CategoryName }
});

结果是:

'First (#1) in My Category (#10)'
'Second (#2) in My Category (#10)'

如果这与它有任何关系,我将连接到 MySQL 数据库。

4

1 回答 1

12

最简单的方法是全部调用它们Id(不区分大小写,所以就a.id可以b.id了);那么你可以使用:

    public void TestMultiMapWithSplit()
    {
        var sql = @"select 1 as Id, 'abc' as Name, 2 as Id, 'def' as Name";
        var product = connection.Query<Product, Category, Product>(sql,
           (prod, cat) =>
           {
               prod.Category = cat;
               return prod;
           }).First();
        // assertions
        product.Id.IsEqualTo(1);
        product.Name.IsEqualTo("abc");
        product.Category.Id.IsEqualTo(2);
        product.Category.Name.IsEqualTo("def");
    }

如果您不能这样做,则有一个可选的splitOn( string) 参数,它采用逗号分隔的列列表来处理拆分。

于 2011-05-19T10:10:59.467 回答