7

我正在尝试验证具有“可选”字段的对象，因为它们可能存在也可能不存在。但是当它们存在时，这些字段应该符合特定的类型定义（而不是无）。

在下面的示例中，“size”字段是可选的，但允许 None。我希望“大小”字段是可选的，但如果存在，它应该是一个浮点数。

from pydantic import BaseModel

class Foo(BaseModel):
    count: int
    size: float = None  # how to make this an optional float? 

 >>> Foo(count=5)
 Foo(count=5, size=None)  # GOOD - "size" is not present, value of None is OK


 >>> Foo(count=5, size=None)
 Foo(count=5, size=None) # BAD - if field "size" is present, it should be a float

 # BONUS
 >>> Foo(count=5)
 Foo(count=5)  # BEST - "size" is not present, it is not required to be present, so we don't care about about validating it all.  We are using Foo.json(exclude_unset=True) handles this for us which is fine.
4

2 回答 2

3

可以使用验证器。

from pydantic import BaseModel, ValidationError, validator

class Foo(BaseModel):
    count: int
    size: float = None

    @validator('size')
    def size_is_some(cls, v):
        if v is None:
            raise ValueError('Cannot set size to None')
        return float(v)

这按预期工作：

>>> Foo(count=5)
Foo(count=5, size=None)

>>> Foo(count=5, size=1.6)
Foo(count=5, size=1.6)

>>> Foo(count=5, size=None)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "[venv]/lib/python3.6/site-packages/pydantic/main.py", line 283, in __init__
    raise validation_error
pydantic.error_wrappers.ValidationError: 1 validation error for Foo
size
  Cannot set size to None (type=value_error)
于 2020-02-19T13:32:29.150 回答
0 
from pydantic import BaseModel
from typing import Optional

class Foo(BaseModel):
    count: int
    size: Optional[float]


obj = Foo(count=5)
obj_2 = Foo(count=5, size=1.6)

# count=5 size=None
print(obj)
# count=5 size=1.6
print(obj_2)

这可能会令人困惑，但输入中的可选类型将使您有可能拥有“可选”字段

于 2022-01-04T13:09:28.073 回答