我已经解决了以下约束处理任务。你能验证它是否正确吗？
One of the prisoners of a high-level security prison sees a way to escape. Almost
free, he reaches a corridor of 20 meters long, guarded by 5 cameras, behind
which is the exit. In Figure 3, we provide a schematic overview of the corridor.
The prisoner has only 10 seconds to reach the end of the corridor and may
not be noticed by the cameras in doing so. After 10 seconds, or when seen by a
camera, the prison is put under total lock-down, which will prevent his escape.
We will consider the following constraints:
• A camera can only see 3 meters and cannot see its own position. E.g., the
camera at position 9 is able to see the positions 6, 7 and 8, or 10, 11 and
12, depending on the orientation of the camera.
• At time point 0, all cameras are oriented towards the end of the corridor.
Thus, the camera at position 9 sees positions 10, 11 and 12.
• Every two seconds the cameras change their orientation. Thus, at time
point 2 the camera at position 9 will see the positions 6, 7 and 8.
• Every second, the prisoner can move 0, 1, 2 or 3 meters forward. He
cannot move backward. Thus, if the prisoner is standing at position 2 at
time point 2, then, at time point 3, he can be on position 2, 3, 4 or 5.
Formulate the problem above as a constraint problem. Come up with a useful
representation of the problem in terms of the constraint processing tool. Provide
an explanation of indices, variables and domains. Furthermore, provide for every
introduced constraint, the meaning of the constraint in natural language.
这是我的解决方案，希望你们帮我检查哪里做错了：
***MY VARIABLES***
Name: T, domain: 0..10 // T = the time from 0 to 10 seconds
Name: P, domain: 0..3 // P = Prisoner can move 0, 1, 2, 3 meters
Name: C1, domain: 2 // C1 = camera 1
Name: C2, domain: 4 // C2 = camera 2
Name: C3, domain: 9 // C3 = camera 3
Name: C4, domain: 12 // C4 = camera 14
Name: C5, domain: 17 // C5 = camera 5
Name: View1, domain: -1..5 // camera1 view
Name: View2, domain: 1..7 // camera2 view
Name: View3, domain: 6..12 // camera3 view
Name: View4, domain: 9..15 // camera4 view
Name: View5, domain: 14..20 // camera5 view
我的约束
我以这样一种方式声明了约束，即每次当时间为偶数时，摄像机的视图交替改变，但当时间为偶数时，只有囚犯可以移动。
Constraint: (T=0/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
Constraint: (T=1/\P(i)), range: i>0
Constraint: (T=2/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1
Constraint: (T=3/\P(i)), range: i>0
Constraint: (T=4/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
Constraint: (T=5/\P(i)), range: i>0
Constraint: (T=6/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1
Constraint: (T=7/\P(i)), range: i>0
Constraint: (T=8/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
Constraint: (T=9/\P(i)), range: i>0
Constraint: (T=10/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1
伙计们，我知道我做错了什么，所以请帮助我纠正它。
谢谢你的帮助。我昨天发布了一个类似的问题，所以如果你想知道变量和约束的语法，那么这是链接： 这篇文章中的变量和约束语法
谢谢你的帮助