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我正在编写一个Android 应用程序,它将使用sharepoint 2010 中lists.amx 服务的getlist() 方法。我正在使用kso​​ap2-android 来处理我的soap 消息。当我尝试进行身份验证时,我得到一个 xmlpullparser 异常,预期 START_TAG... 为什么下面的代码不会对共享点服务器进行身份验证?

这是我的代码:

public class SharepointList extends Activity {
private static final String SOAP_ACTION = "http://schemas.microsoft.com/sharepoint/soap/GetList";
private static final String METHOD_NAME = "GetList";
private static final String NAMESPACE = "http://schemas.microsoft.com/sharepoint/soap/" ;
private static final String URL = "http://<ip of sharepoint server>/_vti_bin/lists.asmx";

private TextView result;
private Button btnSubmit;

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    result = (TextView)findViewById(R.id.textView1);
    btnSubmit = (Button)findViewById(R.id.button1);
    btnSubmit.setOnClickListener(new OnClickListener(){
        public void onClick(View v) {
            if(v.getId() == R.id.button1)
            {
                String list = getMobileTestList();
                result.setText(list);
            }

        }

    });


}
private String getMobileTestList()
{
    PropertyInfo pi = new PropertyInfo();
    pi.setName("listName");
    pi.setValue("Mobile Test List");

    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
    request.addProperty(pi);

    String authentication = android.util.Base64.encodeToString("username:password".getBytes(), android.util.Base64.DEFAULT);
    List<HeaderProperty> headers = new ArrayList<HeaderProperty>();
    headers.add(new HeaderProperty("Authorization","Basic " +authentication));
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);


    HttpTransportSE transport = new HttpTransportSE(URL);
    try
    {
        transport.debug = true;
        transport.call(SOAP_ACTION, envelope, headers);
        //transport.call(SOAP_ACTION, envelope);
        Object result = envelope.getResponse();
        return result.toString();

    }
    catch(Exception e)
    {
        return e.toString();
    }
}
}

这是 transport.requestdump(删除了前面的“<”):

  • v:信封 xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema" xmlns:c="http: //schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
    • v:标题 />
    • v:身体>
      • GetList xmlns="http://schemas.microsoft.com/sharepoint/soap/" id="o0" c:root="1">
        • listName i:type="d:string">手机测试列表
    • /获取列表>
    • /v:身体>
  • /v:信封>

这是 transport.responsedump(删除了前面的“<”):

  • !DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN""http://www.w3.org/TR/html4/strict.dtd">
    • HTML>
    • 头>
      • TITLE>错误请求
      • META HTTP-EQUIV="Content-Type" Content="text/html; charset=us-ascii">
    • /头>
    • 身体>
      • h2>错误的请求 - 无效的主机名
      • hr> p>HTTP 错误 400。请求主机名无效。

    • /身体>
  • /HTML>
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1 回答 1

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也许尝试以下方法:

String authentication = android.util.Base64.encodeToString("username:password".getBytes(), android.util.Base64.NO_WRAP);

默认情况下,Android Base64 实用程序会在编码字符串的末尾添加一个换行符。这会使 HTTP 标头无效并导致“错误请求”。

Base64.NO_WRAP标志可以防止这种情况并保持标题完好无损。

于 2011-07-01T10:47:34.750 回答