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我正在尝试根据我的数组值运行 switch 语句。

我需要做一个while循环，遍历我的整个数组，如果数组位value = 0我需要它运行case 0 ，如果value = 1我需要它运行位case 1

我需要运行 while 循环，直到它完成对数组值和相应的 case 切换函数的运行

我正在处理的代码：

        Scanner scan = new Scanner(System.in);
        System.out.println("What position do you want the top card to be moved to?");
        System.out.println("Enter \"1\", \"2\", \"3\", \"4\" or \"5\"");
        int i = scan.nextInt();
        int in = i -1;
        //System.out.println(i);
        String binaryString = Integer.toBinaryString(in);
        System.out.println(binaryString);
        int foo = Integer.parseInt(binaryString, 2);
        System.out.println(foo);

        String[] array = binaryString.split("\\|", -1);
            System.out.println(Arrays.toString(array));


            switch (foo) {
            case 0:
            cardForceOutShuffle();
            index = 51;
            break;
            case 1:
            cardForceInShuffle();
            index = 51;
            break;
            }

请帮忙。

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1 回答 1

0

假设很多事情，这就是我想出的。请更准确地回答您的问题..

我将我的意见作为注释添加到某些代码中。

Scanner scan = new Scanner(System.in);
System.out.println("What position do you want the top card to be moved to?");
System.out.println("Enter \"1\", \"2\", \"3\", \"4\" or \"5\"");
int i = scan.nextInt(); // This can lead to an InputMismatchException. Try to check if your input is an integer before you proceed.
int in = i - 1; // Unnecessary

String binaryString = Integer.toBinaryString(in); // Use i-1 directly
char[] charArray = binaryString.toCharArray(); // Since you need each bit you dont need String.split. Just convert to char[]

for (int j = 0; j < charArray.length; j++) {
    switch (charArray[j]) { // This switch is actually useless, since both cases do the same thing.
    case '0':
        cardForceOutShuffle();
        index = 51; // What is index?
        break;
    case '1':
        cardForceOutShuffle();
        index = 51;
        break;
    }
}
scan.close(); // Close your resources if they are not needed anymore.
于 2019-12-20T14:59:54.733 回答