我在测试此功能时遇到问题。我不知道如何测试checkAuth
何时decode
被嘲笑。
import decode from "jwt-decode";
export const checkAuth = () => {
const token = localStorage.getItem("token");
if (!token) {
return false;
}
try {
const { exp } = decode(token);
if (exp < new Date().getTime() / 1000) {
return false;
}
} catch (e) {
console.log(e); // 'Invalid token specified: Cannot read property \'replace\' of undefined'
return false;
}
return true;
};
我的测试不起作用。它具有原始功能。
import { Auth, AuthAdmin, checkAuth, AppContent, AuthApp } from "./Auth";
import LocalStorageMock from "../../../mocks/localStorageMock";
import decode from "jwt-decode";
global.localStorage = new LocalStorageMock();
describe("auth", () => {
localStorage.setItem("token", "fake_token_user");
const token = localStorage.getItem("token");
it("allows the user to login successfully", async () => {
const decode = jest.fn(token => {
return {
exp: new Date().getTime() / 1000 - 1,
iat: 1575751766,
userData: { isAdmin: true, login: "one92tb", userId: 1 }
};
});
//const { exp } = decode(token);
expect(token).toBeDefined();
expect(checkAuth()).toBe(true) // It runs original decode function
});
});
有人可以向我解释如何解决这个问题吗?