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我正在用 JSPsych 编写一个实验，其中有十个条件。我需要根据条件呈现具有不同频率的五个图像的数组。

我已经设法使用 for 循环和 randomize.sampleWithReplacement 进行某种工作，但它没有以我需要的频率呈现图像。

例如，在一种情况下，我希望图像 5 被呈现 8 次，图像 4 被呈现 6 次，依此类推。

有谁知道我如何使用插件和 JSPsych 函数来实现它？

到目前为止，这是我的代码：

if (cond2 == 'uniform') {
  var ratings_r = jsPsych.randomization.repeat(ratings, 4);
  for (var i = 0; i < ratings_r.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=" + ratings_r[i] + "><br><br><br>"
      }
    ]
  });
} 
} if (cond2 == 'left-skew') {
  var ratings_ls = jsPsych.randomization.sampleWithReplacement(ratings, 20, [2, 1, 1, 1, 1]);
  console.log(ratings_ls)
  for (var i = 0; i < ratings_ls.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=" + ratings_ls[i] + "><br><br><br>"
    }
    ]
    });
  }
  } else {
  var ratings_rs = jsPsych.randomization.sampleWithReplacement(ratings, 20, [1, 1, 1, 1, 4]);
  console.log(ratings_rs)
  for (var i = 0; i < ratings_rs.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=" + ratings_rs[i] + "><br><br><br>"
    }
    ]
    });
  }

  };

它适用于第一个条件（因为这非常简单）。

这只是我在 JSPsych 中编写的第二个实验，所以我是一个新手，如果能提供任何帮助，我将不胜感激！

- - - - - - - - - 更新 - - - - - - -

我现在有这个：

if (cond2 == 'uniform') {
  var uni = jsPsych.randomization.sampleWithoutReplacement([5, 5, 5, 5, 4, 4, 4, 4, 3, 3, 3, 3, 2, 2, 2, 2, 1, 1, 1, 1]);
  console.log(uni);
  for (var i = 0; i < uni.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=" + ratings[i] + "><br><br><br>"
      }
    ]
  });
}
} else if (cond2 == 'left-skew') {
  var lesk = jsPsych.randomization.sampleWithoutReplacement([5, 5, 5, 5, 5, 5, 5, 5, 4, 4, 4, 4, 4, 4, 3, 3, 3, 2, 2, 1]);
  console.log(lesk);
  for (var i = 0; i < lesk.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=" + ratings[i] + "><br><br><br>"
    }
    ]
    });
  }
  } else {
  var risk = jsPsych.randomization.sampleWithoutReplacement([1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 5]);
  console.log(risk);
  for (var i = 0; i < risk.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=" + ratings[i] + "><br><br><br>"
    }
    ]
    });
  }

  };

我创建了一个 shuffled 数组，它规定了呈现频率，但我不确定如何合并到循环中，以便图像呈现该次数。图像标记为 1、2、3、4、5。

4

1 回答 1

0

终于想出了一些可行的方法。

if (cond2 == 'uniform') {
  var uni = jsPsych.randomization.sampleWithoutReplacement([5, 5, 5, 5, 4, 4, 4, 4, 3, 3, 3, 3, 2, 2, 2, 2, 1, 1, 1, 1], 20);
  console.log(uni);
  for (var i = 0; i < uni.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=./img/" + uni[i] + ".png><br><br><br>"
      }
    ]
  });
}
} else if (cond2 == 'left_skew') {
  var lesk = jsPsych.randomization.sampleWithoutReplacement([5, 5, 5, 5, 5, 5, 5, 5, 4, 4, 4, 4, 4, 4, 3, 3, 3, 2, 2, 1], 20);
  console.log(lesk);
  for (var i = 0; i < lesk.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=./img/" + lesk[i] + ".png><br><br><br>"
    }
    ]
    });
  }
  } else {
  var risk = jsPsych.randomization.sampleWithoutReplacement([1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 5], 20);
  console.log(risk);
  for (var i = 0; i < risk.length; i++) {
  timeline.push({
    type: "html-button-response",
    choices: ['Click here to continue'],
    button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
    on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
    is_html: true,
    timeline: [{
      stimulus: "<img src=./img/" + risk[i] + ".png><br><br><br>"
    }
    ]
    });
  }

  };

So I basically created an array specifying the frequency for each condition and called that in the for loop.
于 2019-12-05T00:09:56.247 回答