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我有一个名为uf包含 JSON 对象数组的列。这是一个样机：

[
    {"type": "browserId", "name": "", "value": "unknown"},
    {"type": "campaign", "name": "", "value": "om_227dec0082a5"},
    {"type": "custom", "name": "2351350529", "value": "10148"},
    {"type": "custom", "name": "9501713387", "value": "true"},
    {"type": "custom", "name": "9517735577", "value": "true"},
    {"type": "custom", "name": "9507402548", "value": "true"},
    {"type": "custom", "name": "9733902068", "value": "true"}
]

我试图将其作为子记录，但由于某种原因，我找不到首先将其取消嵌套的正确方法。然后我注意到我的整个数组被包装到另一个 JSON 对象中。

这就是我所在的位置：

我尝试了简单的选择并注意到结果是：

[{type=[{"type": "browserId", "name": "", "value": "ff"}, name=null, value=null}]

该列的定义如下：

{
    "Name": "uf",
    "Type": "array<struct<type:string,name:string,value:string>>"
}

定义是否不正确，这就是为什么我将整个数组包装在另一个 json 数组中的原因？

-- 编辑 这是我的 csv 文件的示例（制表符分隔）。过去两天试图查看是否是关于 JSON 的问题导致 Glue 无法将列识别为 JSON 数组，但我创建了一个新列，其中包含正确分配的简单 JSON 数组，array<struct但在查询后我遇到了与上面完全相同的问题

timestamp   project_id  campaign_id experiment_id   variation_id    layer_holdback  audience_names  end_user_id uuid    session_id  snippet_revision    user_ip user_agent  user_engine user_engine_version referer global_holdback event_type  event_name  uf  active_views    event_features  event_metrics   event_uuid
1570326511  74971132    11089500404 11097730080 11078120202 false   []  oeu1535997971348r0.4399811351004357     AUTO    6540    5.91.170.0  Mozilla/5.0 (Linux; Android 7.0; SAMSUNG SM-G925F Build/NRD90M) AppleWebKit/537.36 (KHTML, like Gecko) SamsungBrowser/9.2 Chrome/67.0.3396.87 Mobile Safari/537.36  js  0.128.0 https://www.zavamed.com/uk/account/ false   view_activated  10832783364 [{"type": "browserId", "name": "", "value": "unknown"}, {"type": "device", "name": "", "value": "mobile"}, {"type": "device_type", "name": "", "value": "phone"}, {"type": "referrer", "name": "", "value": "https:\/\/www.google.co.uk\/"}, {"type": "source_type", "name": "", "value": "campaign"}, {"type": "currentTimestamp", "name": "", "value": "-1631518596"}, {"type": "offset", "name": "", "value": "-60"}]    []  []  []  4926a5f1-bbb5-4553-9d0b-b26f773fa0f4
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1 回答 1

2

我将包含您提供的内容的示例 csv 文件上传到 S3。然后我在上面跑了一个胶水爬行器。这是我最终得到的表模式：

CREATE EXTERNAL TABLE `question_58765672`(
  `timestamp` bigint, 
  `project_id` bigint, 
  `campaign_id` bigint, 
  `experiment_id` bigint, 
  `variation_id` bigint, 
  `layer_holdback` boolean, 
  `audience_names` array<string>, 
  `end_user_id` string, 
  `uuid` string, 
  `session_id` string, 
  `snippet_revision` bigint, 
  `user_ip` string, 
  `user_agent` string, 
  `user_engine` string, 
  `user_engine_version` string, 
  `referer` string, 
  `global_holdback` boolean, 
  `event_type` string, 
  `event_name` bigint, 
  `uf` string, 
  `active_views` array<string>, 
  `event_features` array<string>, 
  `event_metrics` array<string>, 
  `event_uuid` string)
ROW FORMAT DELIMITED 
  FIELDS TERMINATED BY '\t' 
STORED AS INPUTFORMAT 
  'org.apache.hadoop.mapred.TextInputFormat' 
OUTPUTFORMAT 
  'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'
LOCATION
  's3://__S3_PATH_IN_MY_BUCKET__/'
TBLPROPERTIES (
  'CrawlerSchemaDeserializerVersion'='1.0', 
  'CrawlerSchemaSerializerVersion'='1.0', 
  'UPDATED_BY_CRAWLER'='some-crawler', 
  'areColumnsQuoted'='false', 
  'averageRecordSize'='553', 
  'classification'='csv', 
  'columnsOrdered'='true', 
  'compressionType'='none', 
  'delimiter'='\t', 
  'objectCount'='1', 
  'recordCount'='2', 
  'sizeKey'='1109', 
  'skip.header.line.count'='1', 
  'typeOfData'='file')

如您所见，它将列标识uf为字符串，对此我并不感到惊讶。为了取消嵌套此列，我必须手动将其转换为正确的类型ARRAY(JSON)：

SELECT
    "timestamp",
    _unnested_column
FROM
    "stackoverflow"."question_58765672",
    UNNEST( CAST(json_parse(uf) AS ARRAY(JSON)) ) AS t(_unnested_column)

结果：

    timestamp   _unnested_column
1   1570326511  {"name":"","type":"browserId","value":"unknown"}
2   1570326511  {"name":"","type":"device","value":"mobile"}
3   1570326511  {"name":"","type":"device_type","value":"phone"}
4   1570326511  {"name":"","type":"referrer","value":"https://www.google.co.uk/"}
5   1570326511  {"name":"","type":"source_type","value":"campaign"}
6   1570326511  {"name":"","type":"currentTimestamp","value":"-1631518596"}
7   1570326511  {"name":"","type":"offset","value":"-60"}

然后我想创建一个athena views，其中列uf将被正确投射：

CREATE OR REPLACE VIEW question_58765672_v1_json AS
SELECT
    CAST(json_parse(uf) AS ARRAY(JSON)) as uf
    -- ALL other columns from your table
FROM 
    "stackoverflow"."question_58765672"

但是，我收到以下错误：

uf 列的列类型无效：不支持的 Hive 类型：json

我的猜测是，列的模式uf对于胶水爬虫来说太复杂了，无法正确识别它，或者只是不被使用的 Serde 支持，即'org.apache.hadoop.mapred.TextInputFormat'或'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'.

于 2019-11-18T17:30:26.100 回答