3 
private void AddValue(string strValue)

{

      //get the maximum id for Lists first

      int MaxID = DataOperations.ReturnMaxIDInATable("Lists", connString);
      int iSqlStatus = 0;
      string query = "INSERT INTO Lists(ID, ListName, ListValue) 
         VALUES(@MaxID, @ListName, @ListValue)";

      MaxID++;

      OleDbConnection dbConn = new OleDbConnection(connString);
      OleDbCommand dbComm = new OleDbCommand();

      dbComm.Parameters.Clear();
      try
      {
                dbComm.CommandText = query;
                dbComm.CommandType = CommandType.Text;

                OleDbParameter IDParam = new OleDbParameter();
                IDParam.ParameterName = "@MaxID";
                IDParam.OleDbType = OleDbType.BigInt;
                IDParam.Value = MaxID;
                dbComm.Parameters.Add(IDParam);

                dbComm.Parameters.AddWithValue("@ListName", ListName);
                dbComm.Parameters.AddWithValue("@ListValue", strValue);
                dbComm.Connection = dbConn;
                DataAccess.HandleConnection(dbConn);

                iSqlStatus = Convert.ToInt16(dbComm.ExecuteNonQuery());

                //Now check the status
                if (iSqlStatus != 0)
                {
                    //DO your failed messaging here
                    //return false;
                }
                else
                {
                    //Do your success work here
                    //dbComm.
                    //return true;
                }
      }
      catch (Exception ex)
      {
                MessageBox.Show(ex.Message, "Error inserting value in "
                                            + ListName + ","
                                            + strValue);
                //return false;
      }
      finally
      {
                DataAccess.HandleConnection(dbConn);
      }

}
4

4 回答 4

5

我相信您在通过OleDbCommand执行 SQL 时需要对参数使用问号（而SqlCommand使用 @）。例子：

INSERT INTO Lists (ID, ListName, ListValue) VALUES (?, ?, ?)

您只需要按照它们在 SQL 中出现的顺序添加参数。

于 2011-05-03T13:33:36.793 回答
0

如果在查询的开头包含子句“DECLARE”，将起作用：

string query = "DECLARE @MaxID as bigint, "+
                      " @ListName as Varchar(100), "+
                      " @ListValue As Varchar(100) " +
        " INSERT INTO Lists(ID, ListName, ListValue) " +
            " VALUES(@MaxID, @ListName, @ListValue)"

此外，正确的解决方案是将您的驱动程序更改为 SQLClient 和 OracleClient。不建议将 OleDb 用于 SQL 2005 及更高版本。

于 2016-07-05T11:09:34.183 回答
-2

这似乎可以解决问题..

string query = string.Format("INSERT INTO Lists(ID, ListName, ListValue) 
         VALUES({0}, '{1}', '{2}')", MaxID, ListName, strValue);

尽管我对此有所保留，例如如果我需要添加日期值怎么办？

于 2011-05-16T13:19:26.573 回答
-2

以下片段应为：

IDParam.ParameterName = "MaxID";
IDParam.OleDbType = OleDbType.BigInt;
IDParam.Value = MaxID;
dbComm.Parameters.Add(IDParam);

dbComm.Parameters.AddWithValue("ListName", ListName);
dbComm.Parameters.AddWithValue("ListValue", strValue);
于 2011-05-03T13:35:15.657 回答