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我在将 Treapnode 插入 treap 时遇到问题。它接受 3 个参数。添加(E键,P优先级,treapnode x)。我已经尝试了很多事情并不断收到空指针异常。

我尝试在左右树中检查 null 情况。

private TreapNode add (E key, P priority, TreapNode x)
        throws ElementFoundException {

    // For You To Complete
    int compare = key.compareTo(x.element());
    if (x == null){
        return new TreapNode(key, priority);
    }

    //root is larger than the key

    else if (compare == 0) {
        throw new ElementFoundException("Element was found, and tree was not changed.");
    } else if (compare < 0) {
        if (x.left() == null) {
         //TreapNode y = new TreapNode(key, priority);
            TreapNode y = x.left;
            x.left = y.right;
            y.right = x;
            return y;
        } else {
            x.left = add(key, priority, x.left());
        }


    }
    //root is smaller than the key
    else if (compare > 0) {
        if (x.right() == null) {
            //TreapNode y = new TreapNode(key, priority);
            TreapNode z = x.right;
            x.right = z.left;
            z.left = x;
            return z;
        }

    }
    return x;
}
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1 回答 1

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这是你做错了x.right()。情况也是如此x.left()

if (x.right() == null) {
        //TreapNode y = new TreapNode(key, priority);
        TreapNode z = x.right; // z = null
        x.right = z.left;  // z.left will throw NPE

应该

if (x.right() == null) {
   x.right() = new TreapNode(key, priority);
   return x; // return parent node 
}

另外,我认为这也是一个错误的比较,int不能null但是Integerclass可以

int compare = key.compareTo(x.element());  //comoareTo return an int 
if (x == null){  // does not make sense to compare and int type to Object type
  ....
}

如需深入了解,请阅读此页面https://www.geeksforgeeks.org/binary-search-tree-set-1-search-and-insertion/

于 2019-11-03T08:20:09.167 回答