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我想从 CNN RSS 提要中抓取新闻文章并获取每篇抓取文章的链接。这与 Python NewsPaper 库配合得很好,但不幸的是,我无法获得可用格式的输出,即列表或字典。

我想将抓取的链接添加到一个 SINGLE 列表中,而不是许多单独的列表中。

    import feedparser as fp
    import newspaper
    from newspaper import Article

    website = {"cnn": {"link": "http://edition.cnn.com/", "rss": "http://rss.cnn.com/rss/cnn_topstories.rss"}}

    for source, value in website.items():
        if 'rss' in value:
            d = fp.parse(value['rss']) 
            #if there is an RSS value for a company, it will be extracted into d

            for entry in d.entries:
                if hasattr(entry, 'published'):
                    article = {}
                    article['link'] = entry.link
                    print(article['link'])

输出如下:

http://rss.cnn.com/~r/rss/cnn_topstories/~3/5aHaFHz2VtI/index.html
http://rss.cnn.com/~r/rss/cnn_topstories/~3/_O8rud1qEXA/joe-walsh-trump-gop-voters-sot-crn-vpx.cnn
http://rss.cnn.com/~r/rss/cnn_topstories/~3/xj-0PnZ_LwU/index.html
.......

我想要一个包含所有链接的列表,即:

    list =[http://rss.cnn.com/~r/rss/cnn_topstories/~3/5aHaFHz2VtI/index.html , http://rss.cnn.com/~r/rss/cnn_topstories/~3/_O8rud1qEXA/joe-walsh-trump-gop-voters-sot-crn-vpx.cnn , http://rss.cnn.com/~r/rss/cnn_topstories/~3/xj-0PnZ_LwU/index.html ,... ]

我尝试通过 for 循环附加内容,如下所示:

    for i in article['link']:
        article_list = []
        article_list.append(i)
        print(article_list)

但是输出是这样的:

['h']
['t']
['t']
['p']
[':']
['/']
['/']
['r']
['s']
...

有谁知道另一种方法,如何将内容放入一个列表中?或者一个字典如下:

    dict = {'links':[link1 , link2 , link 3]}

非常感谢您的帮助!!

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1 回答 1

0

尝试像这样修改您的代码,看看它是否有效:

article_list = []
for entry in d.entries:
            if hasattr(entry, 'published'):
                article = {}
                article['link'] = entry.link
                article_list.append(article['link'])
于 2019-10-21T20:49:19.957 回答