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您没有p ∨ q此示例的假设。所以,你必须(assume hpqr, _)直接从 到and_intro。我的意思是,像
p ∨ q
(assume hpqr, _)
and_intro
example (p q r : Prop) : ((p ∨ q) → r) → (p → r) ∧ (q → r) := assume hpqr, and.intro (assume p, _) (assume q, _)