假设我有以下两个表
(clsql:def-view-class class-a ()
((field-one :type integer
:db-kind :key
:db-constraints :auto-increment)
(field-two :type string
:initarg :two
:db-constraints :not-null)))
(clsql:def-view-class class-b ()
((b-one :type integer
:initarg :b-one
:db-kind :key)))
(clsql:create-view-from-class 'class-a)
(clsql:create-view-from-class 'class-b)
现在我想要在 class-b 中没有对应条目的 class-a 条目。(“对应”表示 class-a.field-one 映射到 class-bb-one。)假设 class-a 有以下两个条目:
(clsql:update-records-from-instance (make-instance 'class-a :two "hello"))
(clsql:update-records-from-instance (make-instance 'class-a :two "world"))
因此,要发出的查询将是:
(clsql:select 'class-a :from [class-a] ; class-b is added "magically"
:where [not [in [class-a field-one]
[select [class-b b-one] :from [class-b]
:where [= [class-a field-one]
[class-b b-one]]]]])
但是,这也增加了 b 类。(由于有目的的错误,我将查询执行为:)
SELECT CLASS_A.FIELD_ONE,CLASS_A.FIELD_TWO FROM CLASS_A,CLASS_B
WHERE (NOT ((CLASS_A.FIELD_ONE
IN (SELECT CLASS_B.B_ONE FROM CLASS_B
WHERE (CLASS_A.FIELD_ONE = CLASS_B.B_ONE)))))
另一方面,
(clsql:select [*] :from [class-a] ; see the [*]
:where [not [in [class-a field-one]
[select [class-b b-one] :from [class-b]
:where [= [class-a field-one]
[class-b b-one]]]]])
被翻译成预期的:
SELECT * FROM CLASS_A
WHERE (NOT ((CLASS_A.FIELD_ONE
IN (SELECT CLASS_B.B_ONE FROM CLASS_B
WHERE (CLASS_A.FIELD_ONE = CLASS_B.B_ONE)))))
这是一个错误还是这个翻译背后有一些原因?