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The main thing i need to do is extend a model DetailView page with a specific custom python function. That function need to be called from DetailView page and return some data, depending on the parameter entered by user into custom form on DetailView. That data, responded by custom function, i need to display on the same DetailView page, without database record, when user enter a form field value and press 'submit'. I think to implement that function by custom tag, which is located in /app/templatetags/func.py 

#/app/templatetags/func.py

from django import template
register = template.Library()

def get_data(current_version, previous_version, some_data):
    return current_version+' works!'

and call it in template, something like that:

<!--templates/detail/article_detail.html-->

{% load func %}
...
{% get_data article_object.value %}

<form action="" method="get">
    {{ form }}
    <input type="submit" value="Compare">
</form>
...

it works then i trying to specify an argument here in template. But i cannot understand how to take it from the form. Here is views.py:

class ArticleDetailView(LoginRequiredMixin, UserPassesTestMixin, DetailView):
    model = Article
    context_object_name = 'article_object'
    template_name = 'detail/article_detail.html'
    login_url = 'login'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['form'] = GetChangelog()
        return context

forms.py

class GetChangelog(forms.Form):
    diff_version = forms.CharField(label='difference',max_length=10)

Looks like it's impossible to pass a parameter through the url, because of that. Imagine that my article detail view page has an url: http://blog.com/articles/4 ; when i put some data to the form and press submit , it becomes http://blog.com/articles/4?diff_ver=4, but i find myself on the same page, while in the urls i have pointed that record:

#urls.py

...

path('articles/<int:pk>?diff_ver=<str:diff_ver>', ArticleDetailView.as_view(), name='article_changelog')

According to my idea when url have changed to http://blog.com/articles/4?diff_ver=4, it must to redirect me into another view with some additional data from my custom function from func.py, which will recieve diff_ver as an argument. Or may be some another approaches are acceptable here?

UPDATE it can be done easily by context, thank to @dirkgroten:

class ArticleDetailView(LoginRequiredMixin, UserPassesTestMixin, DetailView):
    model = Article
    context_object_name = 'article_object'
    template_name = 'detail/article_detail.html'
    login_url = 'login'

    def get_context_data(self, **kwargs):
        context['parameter'] = self.request.GET.get('diff_version')
        context = super().get_context_data(**kwargs)
        context['form'] = GetChangelog()
        return context

and in template:

<!--templates/detail/article_detail.html-->

{% load func %}
...
{% get_data parameter %}

<form action="" method="get">
    {{ form }}
    {{ parameter }}
    <input type="submit" value="Compare">
</form>
...
4

1 回答 1

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当您使用 GET 提交表单时，表单参数将作为查询组件附加到 URL，如示例中所示?diff_ver=4。这些查询组件不是URL路径组件的一部分，因此 Django URL 模式解析不考虑这些组件。

但就像POST请求一样，您可以使用 获取提交的参数request.POST，它们是request.GET您视图中字典的一部分。所以request.GET.get('diff_ver')将返回提交的值，或者None如果没有提交任何内容。

于 2019-09-03T07:58:35.237 回答