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我有一个像这样生成的视图：

oneView = [[UIView alloc] initWithFrame:CGRectMake(x, y , w, h)];
oneView.tag = i;

UITapGestureRecognizer* recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleSingleTap2:)];
[recognizer setNumberOfTouchesRequired:1];
[oneView addGestureRecognizer:recognizer];
recognizer.delegate = self;
[recognizer release];

- (void)handleSingleTap2:(UITapGestureRecognizer *)recognizer {
    int viewID = recognizer.view.tag;
    NSLog(@"id : %d", viewID);
}

这可行，但如果我用 UIWebView 或 UIImageView 分配替换 UIView 分配，则不再触发触摸事件。

我怎样才能使它工作？

4

3 回答 3

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关于你的问题，UIWebView我建议你看看drawonward的答案：

UIGestureRecognizer 是否适用于 UIWebView？

对于 UIImageView 部分，请参阅本教程：

UIImageView-with-zooming-tapping

我无法在此处粘贴代码，但我认为这将使该区域更清洁且更易于阅读。

于 2011-04-23T13:30:09.503 回答
0

你必须覆盖

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer;

委托函数并返回YES；

于 2011-04-23T13:31:36.277 回答
0

设置 userInteractionEnabled=YES，如果需要，multipleTouchEnabled=YES

于 2011-04-23T13:08:12.387 回答