1

我正在尝试删除 secondaryApp 代码，因为我想阻止该功能 firebaseAuth.createUserWithEmailAndPassword(email,password)在用户创建后自动登录

我参考了下面的代码：

FirebaseOptions.Builder fbo = new FirebaseOptions.Builder();
    fbo.setApiKey("YOUR_WEB_API_KEY");
    fbo.setDatabaseUrl("https://[YOUR_PROJECT_ID].firebaseio.com/");
    fbo.setProjectId("YOUR_PROJECT_ID");
    fbo.setApplicationId("YOUR_APP_ID"); //Tested, App Id is required.
    FirebaseOptions firebaseOptions = fbo.build();
    final FirebaseApp secondaryAuth = FirebaseApp.initializeApp([JAVA_CLASS_NAME].this, firebaseOptions, "secondary_db_auth");

它有效，但是当我尝试调用该方法时

secondaryAuth.delete()

它返回一个错误，说明无法调用该方法，如下图所示。

错误图片

我已经检查了来自 firebase [FirebaseApp.delete()][2] 的文档，并希望它能够正常工作，但事实并非如此。其他一切都解决了，只是delete()不工作

https://firebase.google.com/docs/reference/admin/java/reference/com/google/firebase/FirebaseApp

整个代码实现如下：

private void CreateAccount() {
        String name = username.getText().toString();
        String phone = phoneNumber.getText().toString();
        String email = emailAddress.getText().toString();
        String password = passwordTxt.getText().toString();
        String confirmPassword = confirmPasswordTxt.getText().toString();
        String points = pointsTransfer.getText().toString();
        final DatabaseReference RootRef;
        final FirebaseAuth firebaseAuth;

        FirebaseOptions.Builder fbo = new FirebaseOptions.Builder();
        fbo.setApiKey("YOUR_WEB_API_KEY");
        fbo.setDatabaseUrl("https://[YOUR_PROJECT_ID].firebaseio.com/");
        fbo.setProjectId("YOUR_PROJECT_ID");
        fbo.setApplicationId("YOUR_APP_ID"); //Tested, App Id is required.
        FirebaseOptions firebaseOptions = fbo.build();
        final FirebaseApp secondaryAuth = FirebaseApp.initializeApp([JAVA_CLASS_NAME].this, firebaseOptions, "secondary_db_auth");

        RootRef = FirebaseDatabase.getInstance().getReference().child("Users");
        firebaseAuth = FirebaseAuth.getInstance(secondaryAuth);


        if(TextUtils.isEmpty(name)){
            Toast.makeText(this, "Please insert your user name.", Toast.LENGTH_SHORT).show();
        }
        else if(TextUtils.isEmpty(phone)){
            Toast.makeText(this, "Please insert your phone number.", Toast.LENGTH_SHORT).show();
        }
        else if(TextUtils.isEmpty(email)){
            Toast.makeText(this, "Please insert your phone number.", Toast.LENGTH_SHORT).show();
        }
        else if(TextUtils.isEmpty(password)){
            Toast.makeText(this, "Please insert your password.", Toast.LENGTH_SHORT).show();
        }
        else if(TextUtils.isEmpty(confirmPassword)){
            Toast.makeText(this, "Please insert your password again.", Toast.LENGTH_SHORT).show();
        }
        else if(!password.equals(confirmPassword)){
            Toast.makeText(this, "Password does not match.", Toast.LENGTH_SHORT).show();
        }
        else if(TextUtils.isEmpty(points)){
            Toast.makeText(this, "You need to send some points", Toast.LENGTH_SHORT).show();
        }
        else if(Float.parseFloat(currentUser.getPoints())<Float.parseFloat(points)){
            Toast.makeText(this, "You do not have sufficient points.", Toast.LENGTH_SHORT).show();
        }
        else{
            loadingBar.setTitle("Create Account");
            loadingBar.setMessage("Please wait, we are checking the credentials.");
            loadingBar.setCanceledOnTouchOutside(false);
            loadingBar.show();

            ValidateAccount(name, phone,email, password, confirmPassword,points, RootRef, firebaseAuth);
            secondaryAuth.delete();
        }
    }
4

1 回答 1

2

FirebaseApp.delete()据我在参考文档中看到的，没有任何方法。

一旦您创建了一个FirebaseApp实例，它将在该应用程序的整个生命周期中存在。鉴于FirebaseApp实例非常轻量级，这通常不是问题。

但他们当然可以持有更昂贵的资源，例如服务实例。如果这是您的应用程序所关心的问题，请务必隔离名称应用程序实例及其服务的使用，以便在不再需要它们时进行垃圾收集。

听起来您想检测是否已经初始化了FirebaseApp，您可以通过调用getApps()、循环遍历结果并检查每个结果的名称来做到这一点。或者，您可以调用getInstance("secondary_db_auth")并处理它在应用程序实例尚不存在时引发的异常。

于 2019-07-22T14:44:33.567 回答